VB.NET 中的整数除法舍入
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Integer division rounding in VB.NET
提问by user2472706
When two variables are declared as integer type and you perform
当两个变量被声明为整数类型并且你执行
14/4, you get 4, but when you use integer division, 14\4, you get 3.
14/4，你得到 4，但是当你使用整数除法时，14\4，你得到 3。
I thought when you use integer division it rounds to the closest even number. So 14\4 = 3.5 (4 is the closest even number) should be 4 instead, right?
我认为当你使用整数除法时，它会四舍五入到最接近的偶数。所以 14\4 = 3.5（4 是最接近的偶数）应该是 4，对吧？
回答by fareed
In VB.NET, the /operator is defined to return a floating-point result. It converts the variables to double before performing the division.
在 VB.NET 中，/运算符被定义为返回一个浮点结果。它在执行除法之前将变量转换为 double。
This is not the case in the integer division \where the division is performed without the remainder if the quotient is a decimal (decimals are ignored). For example if the quotient is 3.x, then xis ignored
\如果商是小数（忽略小数），则在整数除法中不是这种情况，在整数除法中，除法没有余数。例如，如果商为3.x，则x忽略
回答by JLRishe
When you cast a floating point number to an integer in VB.NET, the value is rounded to the nearest even number. Apparently rounding a number when converting it to an integer is a behavior that stretches back to the days of the BASIC language.
当您在 VB.NET 中将浮点数转换为整数时，该值将四舍五入为最接近的偶数。显然，在将数字转换为整数时四舍五入是一种可以追溯到 BASIC 语言时代的行为。
However, when performing integer division (with the \operator), the fractional part is simply discarded, no matter what the fractional part is. This is why you get the behavior that you are seeing.
但是，在执行整数除法时（使用\运算符），无论小数部分是什么，小数部分都会被简单地丢弃。这就是为什么你会得到你所看到的行为。
