如何使用 jQuery 创建 JSON 对象
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How to create JSON object using jQuery
提问by user1462958
I have a JSON object in below format:
我有以下格式的 JSON 对象：
temp:[
{
test:'test 1',
testData: [
{testName: 'do',testId:''}
],
testRcd:'value'
},
{
test:'test 2',
testData: [
{testName: 'do1',testId:''}
],
testRcd:'value'
}
],
How can i create JSON object in jquery for above format. I want to create a dynamic JSON object.
如何在 jquery 中为上述格式创建 JSON 对象。我想创建一个动态 JSON 对象。
回答by Tim
Just put your data into an Object like this:
只需将您的数据放入这样的对象中：
var myObject = new Object();
myObject.name = "John";
myObject.age = 12;
myObject.pets = ["cat", "dog"];
Afterwards stringify it via:
然后通过以下方式对其进行字符串化：
var myString = JSON.stringify(myObject);
You don't need jQuery for this. It's pure JS.
为此，您不需要 jQuery。它是纯JS。
回答by Denys Séguret
A "JSON object" doesn't make sense : JSONis an exchange format based on the structure of Javascript object declaration.
“JSON 对象”没有意义：JSON是一种基于 Javascript 对象声明结构的交换格式。
If you want to convert your javascript object to a json string, use JSON.stringify(yourObject);
如果要将 javascript 对象转换为 json 字符串，请使用JSON.stringify(yourObject);
If you want to create a javascript object, simply do it like this :
如果你想创建一个 javascript 对象，只需这样做：
var yourObject = {
test:'test 1',
testData: [
{testName: 'do',testId:''}
],
testRcd:'value'
};
回答by smulholland2
I believe he is asking to write the new json to a directory. You will need some Javascript andPHP. So, to piggy back off the other answers:
我相信他要求将新的 json 写入目录。您将需要一些 Javascript和PHP。因此，要捎带其他答案：
script.js
脚本.js
var yourObject = {
test:'test 1',
testData: [
{testName: 'do',testId:''}
],
testRcd:'value'
};
var myString = 'newData='+JSON.stringify(yourObject); //converts json to string and prepends the POST variable name
$.ajax({
type: "POST",
url: "buildJson.php", //the name and location of your php file
data: myString, //add the converted json string to a document.
success: function() {alert('sucess');} //just to make sure it got to this point.
});
return false; //prevents the page from reloading. this helps if you want to bind this whole process to a click event.
buildJson.php
构建Json.php
<?php
$file = "data.json"; //name and location of json file. if the file doesn't exist, it will be created with this name
$fh = fopen($file, 'a'); //'a' will append the data to the end of the file. there are other arguemnts for fopen that might help you a little more. google 'fopen php'.
$new_data = $_POST["newData"]; //put POST data from ajax request in a variable
fwrite($fh, $new_data); //write the data with fwrite
fclose($fh); //close the dile
?>
回答by engrmukul
How to get append input field value as json like
如何像json一样获取附加输入字段值
temp:[
{
test:'test 1',
testData: [
{testName: 'do',testId:''}
],
testRcd:'value'
},
{
test:'test 2',
testData: [
{testName: 'do1',testId:''}
],
testRcd:'value'
}
],
回答by Thamaraiselvam
Nested JSONobject
嵌套JSON对象
var data = {
view:{
type: 'success', note:'Updated successfully',
},
};
You can parse this data.view.typeand data.view.note
你可以解析这个data.view.type和data.view.note
JSONObject and inside Array
JSON对象和内部数组
var data = {
view: [
{type: 'success', note:'updated successfully'}
],
};
You can parse this data.view[0].typeand data.view[0].note
你可以解析这个data.view[0].type和data.view[0].note
回答by Ravi Anand
var model = {"Id": "xx", "Name":"Ravi"};
$.ajax({ url: 'test/set',
type: "POST",
data: model,
success: function (res) {
if (res != null) {
alert("done.");
}
},
error: function (res) {
}
});
