C++ 将两个整数相除以产生浮点结果
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/12447325/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Dividing two integers to produce a float result
提问by jwbensley
Possible Duplicate:
Why can't I return a double from two ints being divided
可能的重复：
为什么我不能从被分割的两个整数中返回一个双精度值
My C++ program is truncating the output of my integer devision even when I try and place the output into a float. How can I prevent this whilst keeping those to variables (a & b) as integers?
即使当我尝试将输出放入浮点数时，我的 C++ 程序也会截断整数部分的输出。如何在将变量（a 和 b）保持为整数的同时防止这种情况发生？
user@box:~/c/precision$ cat precision.cpp
#include <iostream>
#include <iomanip>
using namespace std;
int main()
{
int a = 10, b = 3;
float ans = (a/b);
cout<<fixed<<setprecision(3);
cout << (a/b) << endl;
cout << ans << endl;
return 0;
}
user@box:~/c/precision$ g++ -o precision precision.cpp
user@box:~/c/precision$ ./precision
3
3.000
回答by cdiggins
Cast the operands to floats:
将操作数转换为浮点数：
float ans = (float)a / (float)b;
