从 PHP 代码中自动删除注释的最佳方法
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Best way to automatically remove comments from PHP code
提问by benlumley
Whats the best way to remove comments from a PHP file?
从 PHP 文件中删除注释的最佳方法是什么？
I want to do something similar to strip-whitespace() - but it shouldn't remove the line breaks as well.
我想做一些类似于 strip-whitespace() 的事情 - 但它也不应该删除换行符。
EG:
例如：
I want this:
我要这个：
<?PHP
// something
if ($whatsit) {
do_something(); # we do something here
echo '<html>Some embedded HTML</html>';
}
/* another long
comment
*/
some_more_code();
?>
to become:
成为：
<?PHP
if ($whatsit) {
do_something();
echo '<html>Some embedded HTML</html>';
}
some_more_code();
?>
(Although if the empty lines remain where comments are removed, that wouldn't be ok).
（虽然如果空行保留在注释被删除的地方，那是不行的）。
It may not be possible, because of the requirement to preserve embedded html - thats whats tripped up the things that have come up on google.
这可能是不可能的，因为需要保留嵌入的 html - 这就是谷歌上出现的问题。
回答by Ionu? G. Stan
I'd use tokenizer. Here's my solution. It should work on both PHP 4 and 5:
我会使用tokenizer。这是我的解决方案。它应该适用于 PHP 4 和 5：
$fileStr = file_get_contents('path/to/file');
$newStr = '';
$commentTokens = array(T_COMMENT);
if (defined('T_DOC_COMMENT'))
$commentTokens[] = T_DOC_COMMENT; // PHP 5
if (defined('T_ML_COMMENT'))
$commentTokens[] = T_ML_COMMENT; // PHP 4
$tokens = token_get_all($fileStr);
foreach ($tokens as $token) {
if (is_array($token)) {
if (in_array($token[0], $commentTokens))
continue;
$token = $token[1];
}
$newStr .= $token;
}
echo $newStr;
回答by Paul Dixon
How about using php -w to generate a file stripped of comments and whitespace, then using a beautifier like PHP_Beautifierto reformat for readability?
如何使用 php -w 生成一个去掉注释和空格的文件，然后使用像PHP_Beautifier这样的美化器重新格式化以提高可读性？
回答by John Tyler
Here's the function posted above, modified to recursively remove all comments from all php files within a directory and all its subdirectories:
这是上面发布的函数，修改为递归删除目录及其所有子目录中的所有 php 文件中的所有注释：
function rmcomments($id) {
if (file_exists($id)) {
if (is_dir($id)) {
$handle = opendir($id);
while($file = readdir($handle)) {
if (($file != ".") && ($file != "..")) {
rmcomments($id."/".$file); }}
closedir($handle); }
else if ((is_file($id)) && (end(explode('.', $id)) == "php")) {
if (!is_writable($id)) { chmod($id,0777); }
if (is_writable($id)) {
$fileStr = file_get_contents($id);
$newStr = '';
$commentTokens = array(T_COMMENT);
if (defined('T_DOC_COMMENT')) { $commentTokens[] = T_DOC_COMMENT; }
if (defined('T_ML_COMMENT')) { $commentTokens[] = T_ML_COMMENT; }
$tokens = token_get_all($fileStr);
foreach ($tokens as $token) {
if (is_array($token)) {
if (in_array($token[0], $commentTokens)) { continue; }
$token = $token[1]; }
$newStr .= $token; }
if (!file_put_contents($id,$newStr)) {
$open = fopen($id,"w");
fwrite($open,$newStr);
fclose($open); }}}}}
rmcomments("path/to/directory");
回答by Tom Haigh
$fileStr = file_get_contents('file.php');
foreach (token_get_all($fileStr) as $token ) {
if ($token[0] != T_COMMENT) {
continue;
}
$fileStr = str_replace($token[1], '', $fileStr);
}
echo $fileStr;
editI realised Ionut G. Stan has already suggested this, but I will leave the example here
编辑我意识到 Ionut G. Stan 已经提出了这个建议，但我会在这里留下这个例子
回答by ZhiJia Tang
a version more powerful : remove all comments in the folder
一个更强大的版本：删除文件夹中的所有评论
<?php
$di = new RecursiveDirectoryIterator(__DIR__,RecursiveDirectoryIterator::SKIP_DOTS);
$it = new RecursiveIteratorIterator($di);
$fileArr = [];
foreach($it as $file){
if(pathinfo($file,PATHINFO_EXTENSION) == "php"){
ob_start();
echo $file;
$file = ob_get_clean();
$fileArr[] = $file;
}
}
$arr = [T_COMMENT,T_DOC_COMMENT];
$count = count($fileArr);
for($i=1;$i < $count;$i++){
$fileStr = file_get_contents($fileArr[$i]);
foreach(token_get_all($fileStr) as $token){
if(in_array($token[0],$arr)){
$fileStr = str_replace($token[1],'',$fileStr);
}
}
file_put_contents($fileArr[$i],$fileStr);
}
回答by Pawel Dubiel
Bash solution: If you want to remove recursively comments from all PHP files starting from the current directory you can write in terminal this one-liner. ( it uses temp1file to store PHP content for processing )
Note that this will strip all white spaces with comments.
Bash 解决方案：如果您想从当前目录开始的所有 PHP 文件中递归删除注释，您可以在终端中编写此单行。（它使用temp1file 来存储 PHP 内容以进行处理）
请注意，这将删除带有注释的所有空格。
find . -type f -name '*.php' | while read VAR; do php -wq $VAR > temp1 ; cat temp1 > $VAR; done
Then you should remove temp1file after.
然后你应该删除temp1文件。
if PHP_BEAUTIFERis installed then you can get nicely formatted code without commentswith
如果PHP_BEAUTIFER安装，那么你可以得到很好的格式化代码，而无需注释与
find . -type f -name '*.php' | while read VAR; do php -wq $VAR > temp1; php_beautifier temp1 > temp2; cat temp2 > $VAR; done;
then remove two files ( temp1, temp2)
然后删除两个文件 ( temp1, temp2)
回答by Marco Demaio
If you already use an editor like UltraEdit, you can open one or multiple PHP file/s and then use a simple Find&Replace (CTRL+R)with the following Perl regexp
如果你已经使用过像UltraEdit这样的编辑器，你可以打开一个或多个 PHP 文件，然后使用一个简单的 Find&Replace (CTRL+R)和下面的 Perl regexp
(?s)/\*.*\*/
Beware the above regexp removes also comments inside a sring, i.e. in echo "hello/*babe*/";the /*babe*/would be removed too. Hence, it could be a solution if you have few files to remove comments, in order to be absolutely sure it does not wrongly replace something that is not a comment you would have to run the Find&Replace command and approve each time what is getting replaced.
谨防上述正则表达式中移除了也评论一个SRING内，即echo "hello/*babe*/";在/*babe*/将太删除。因此，如果您只有很少的文件要删除评论，这可能是一个解决方案，为了绝对确保它不会错误地替换不是评论的内容，您必须运行 Find&Replace 命令并在每次替换内容时进行批准。
回答by Steely Wing
/*
* T_ML_COMMENT does not exist in PHP 5.
* The following three lines define it in order to
* preserve backwards compatibility.
*
* The next two lines define the PHP 5 only T_DOC_COMMENT,
* which we will mask as T_ML_COMMENT for PHP 4.
*/
if (! defined('T_ML_COMMENT')) {
define('T_ML_COMMENT', T_COMMENT);
} else {
define('T_DOC_COMMENT', T_ML_COMMENT);
}
/*
* Remove all comment in $file
*/
function remove_comment($file) {
$comment_token = array(T_COMMENT, T_ML_COMMENT, T_DOC_COMMENT);
$input = file_get_contents($file);
$tokens = token_get_all($input);
$output = '';
foreach ($tokens as $token) {
if (is_string($token)) {
$output .= $token;
} else {
list($id, $text) = $token;
if (in_array($id, $comment_token)) {
$output .= $text;
}
}
}
file_put_contents($file, $output);
}
/*
* Glob recursive
* @return ['dir/filename', ...]
*/
function glob_recursive($pattern, $flags = 0) {
$file_list = glob($pattern, $flags);
$sub_dir = glob(dirname($pattern) . '/*', GLOB_ONLYDIR);
// If sub directory exist
if (count($sub_dir) > 0) {
$file_list = array_merge(
glob_recursive(dirname($pattern) . '/*/' . basename($pattern), $flags),
$file_list
);
}
return $file_list;
}
// Remove all comment of '*.php', include sub directory
foreach (glob_recursive('*.php') as $file) {
remove_comment($file);
}
回答by Deele
For ajax/json responses, I use following PHP code, to remove comments from HTML/JavaScript code, so it would be smaller (about 15% gain for my code).
对于 ajax/json 响应，我使用以下 PHP 代码从 HTML/JavaScript 代码中删除注释，因此它会更小（我的代码增益约为 15%）。
// Replace doubled spaces with single ones (ignored in HTML any way)
$html = preg_replace('@(\s){2,}@', '', $html);
// Remove single and multiline comments, tabs and newline chars
$html = preg_replace(
'@(/\*([^*]|[\r\n]|(\*+([^*/]|[\r\n])))*\*+/)|((?<!:)//.*)|[\t\r\n]@i',
'',
$html
);
Short and effective, but can produce unexpected results, if your code has $itty syntax.
简短而有效，但如果您的代码具有 $itty 语法，则会产生意想不到的结果。
回答by Robi Parvez
Run the command php --strip file.phpin a command prompt (i.e. cmd.exe), then browse to http://www.writephponline.com/phpbeautifier.
php --strip file.php在命令提示符（即cmd.exe）中运行命令，然后浏览到http://www.writephponline.com/phpbeautifier。
Here, file.phpis your own file.
在这里，file.php是您自己的文件。
