将 bash 变量传送到 awk 并存储输出
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Piping a bash variable into awk and storing the output
提问by Andrew Smith
To illustrate my problem,
为了说明我的问题，
TEST="Hi my name is John"
OUTP=`echo $TEST | awk '{print }'`
echo $OUTP
What I would expect this to do is pass the $TEST variable into awk and store the 3rd word into $OUTP.
我希望这样做是将 $TEST 变量传递到 awk 并将第三个字存储到 $OUTP 中。
Instead I get "Hi: not found", as if it is expecting the input to be a file. If I pass just a string instead of a variable, however, there is no problem. What would be the best way to approach this?
相反，我得到“嗨：未找到”，就好像它期望输入是一个文件。但是，如果我只传递一个字符串而不是变量，则没有问题。解决这个问题的最佳方法是什么？
Thanks all!
谢谢大家！
回答by ghostdog74
#!/bin/bash
TEST="Hi my name is John"
set -- $TEST
echo
#!/bin/bash
TEST="Hi my name is John"
var=$(echo $TEST|awk '{print }')
echo $var
回答by bobylapointe
In one line :
在一行中：
echo $(echo "Hi my name is John" | awk '{print }')
回答by Ken Bloom
Your code works for me, as-is.
您的代码按原样对我有用。
[bloom@little-cat-a ~]$ TEST="Hi my name is John"
[bloom@little-cat-a ~]$ OUTP=`echo $TEST | awk '{print }'`
[bloom@little-cat-a ~]$ echo $OUTP
name
回答by Isaac
As with others, this works for me as-is, but perhaps adding double-quotes (") around $TESTin line 2 would help. If not, more specific information about the system on which you are running bash might help.
与其他人一样，这按原样对我有用，但也许在第 2 行中添加双引号 ( ")$TEST会有所帮助。如果没有，有关运行 bash 的系统的更多具体信息可能会有所帮助。
回答by Paused until further notice.
One way to reproduce similar behavior:
重现类似行为的一种方法：
$ alias echo='echo;'
$ echo Hi
Hi: command not found
$ alias
alias echo='echo;'
$ unalias echo
$ echo Hi
Hi
