在 Typescript 中重新导出类
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Reexport class in Typescript
提问by mleko
I have two classes in two files.
我在两个文件中有两个类。
//a.ts
export class A{}
//b.ts
export class B{}
How I can build file c.tsfrom which I could import both classes?
我如何构建可以c.ts从中导入两个类的文件？
import {A, B} from "c";
instead of
代替
import {A} from "a";
import {B} from "b";
I want to make kind of export facade. How to reexport type?
我想做一种出口外观。如何转口类型？
回答by mleko
I found answer by myself
我自己找到了答案
https://www.typescriptlang.org/docs/handbook/modules.html@Re-exports
https://www.typescriptlang.org/docs/handbook/modules.html@Re-exports
Code to do what I wanted
代码做我想做的事
//c.ts
export {A} from "a";
export {B} from "b";
Default export
默认导出
Assuming you have file
假设你有文件
//d.ts
export default class D{}
Re-export have to look like this
重新导出必须看起来像这样
//reexport.ts
export { default } from "d";
or
或者
//reexport.ts
export { default as D } from "d";
What happens here is that you're saying "I want to re-export the default exportof module "D" but with the name of D
这里发生的事情是你说“我想重新导出default export模块“D”但名称为D
