twitter-bootstrap Bootstrap 6 列响应式
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Bootstrap 6-column responsive
提问by user3292126
I'm using a Bootstrap layout for my design and am about to make it responsive and saving needed order. For example the such as this:
我正在为我的设计使用 Bootstrap 布局,并将使其具有响应性并保存所需的顺序。例如这样的:
<div class="row">
<div class="col-sm-4 col-md-2" >div1</div>
<div class="col-sm-4 col-md-2" >div2</div>
<div class="col-sm-4 col-md-2" >div3</div>
<div class="col-sm-4 col-md-2" >div4</div>
<div class="col-sm-4 col-md-2" >div5</div>
<div class="col-sm-4 col-md-2" >div6</div>
</div>
On md – viewports I'll get like this:
在 md – 视口上,我会得到这样的结果:
div1 div2 div3 div4 div5 div6
On sm- viewports:
在 sm- 视口上:
div1 div2 div3
div4 div5 div6
How could I reorder columns to get like this on sm-viewports:
我如何在 sm-viewports 上重新排序列以得到这样的结果:
div1 div3 div5
div2 div4 div6
In others words – every even columns have to go down, and every odd column have to stay up. Is it possible?
换句话说 - 每个偶数列都必须下降,每个奇数列必须保持上升。是否可以?
回答by James Donnelly
Simply introduce a new set of columns:
简单介绍一组新的列:
<div class="row">
<div class="col-sm-4 col-md-4">
<div class="row">
<div class="col-sm-12 col-md-6" >div1</div>
<div class="col-sm-12 col-md-6" >div2</div>
</div>
</div>
<div class="col-sm-4 col-md-4">
<div class="row">
<div class="col-sm-12 col-md-6" >div3</div>
<div class="col-sm-12 col-md-6" >div4</div>
</div>
</div>
<div class="col-sm-4 col-md-4">
<div class="row">
<div class="col-sm-12 col-md-6" >div5</div>
<div class="col-sm-12 col-md-6" >div6</div>
</div>
</div>
</div>
回答by cvrebert
Using the col-*-push-Nand col-*-pull-Ncolumn ordering classesshould do the trick:
使用了col-*-push-N与col-*-pull-N列排序类应该做的伎俩:
<div class="row">
<div class="col-sm-4 col-md-2" >div1</div>
<div class="col-sm-4 col-md-2 col-md-push-2" >div3</div>
<div class="col-sm-4 col-md-2 col-md-push-6" >div5</div>
<div class="col-sm-4 col-md-2 col-md-pull-4" >div2</div>
<div class="col-sm-4 col-md-2 col-md-pull-4" >div4</div>
<div class="col-sm-4 col-md-2" >div6</div>
</div>
CodePen: http://codepen.io/anon/pen/eakfH
代码笔:http://codepen.io/anon/pen/eakfH

