bash 在 shell 中查找除 *.xml 文件之外的所有文件
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find all files except e.g. *.xml files in shell
提问by paweloque
Using bash, how to find files in a directory structure except for *.xml files? I'm just trying to use
使用bash，如何在目录结构中查找*.xml 文件以外的文件？我只是想使用
find . -regex ....
regexe:
正则：
'.*^((?!xml).)*$'
but without expected results...
但没有预期的结果......
or is there another way to achieve this, i.e. without a regexp matching?
还是有另一种方法来实现这一点，即没有正则表达式匹配？
回答by Pepelac
find . ! -name "*.xml" -type f
find . ! -name "*.xml" -type f
回答by verdesmarald
find . -not -name '*.xml'
Should do the trick.
应该做的伎俩。
回答by Andy Lester
Sloppier than the findsolutions above, and it does more work than it needs to, but you could do
比find上面的解决方案更草率，它做的工作比它需要的要多，但你可以做
find . | grep -v '\.xml$'
Also, is this a tree of source code? Maybe you have all your source code and some XML in a tree, but you want to only get the source code? If you were using ack, you could do:
另外，这是一棵源代码树吗？也许您在树中拥有所有源代码和一些 XML，但您只想获取源代码？如果你使用ack，你可以这样做：
ack -f --noxml
回答by glenn Hymanman
with bash:
使用 bash：
shopt -s extglob globstar nullglob
for f in **/*!(.xml); do
[[ -d $f ]] && continue
# do stuff with $f
done
回答by Marius
You can also do it with or-ring as follows:
您也可以使用 or-ring 执行以下操作：
find . -type f -name "*.xml" -o -type f -print
find . -type f -name "*.xml" -o -type f -print
回答by Anselm
Try something like this for a regex solution:
为正则表达式解决方案尝试这样的事情：
find . -regextype posix-extended -not -regex '^.*\.xml$'
