C# 以编程方式设置图像源 (XAML)
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/11267257/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Programmatically set the Source of an Image (XAML)
提问by Villager
I am working on a Windows 8 app. I need to know how to programmatically set the Source of an Image. I assumed that the Silverlight approach would work. However, it doesn't. Does anybody know how to do this? The following will not work:
我正在开发 Windows 8 应用程序。我需要知道如何以编程方式设置图像的来源。我认为 Silverlight 方法会奏效。然而，事实并非如此。有人知道怎么做这个吗？以下将不起作用：
string pictureUrl = GetImageUrl();
Image image = new Image();
image.Source = new Windows.UI.Xaml.Media.Imaging.BitmapImage(new Uri(pictureUrl, UriKind.Relative));
image.Stretch = Stretch.None;
image.HorizontalAlignment = Windows.UI.Xaml.HorizontalAlignment.Left;
image.VerticalAlignment = Windows.UI.Xaml.VerticalAlignment.Center;
I get an Exception that says: "The given System.Uri cannot be converted into a Windows.Foundation.Uri."
我收到一个异常，内容为：“给定的 System.Uri 无法转换为 Windows.Foundation.Uri。”
However, I can't seem to find the Windows.Foundation.Uri type.
但是，我似乎找不到 Windows.Foundation.Uri 类型。
采纳答案by Rico Suter
I just tried
我刚试过
Image.Source = new BitmapImage(
new Uri("http://yourdomain.com/image.jpg", UriKind.Absolute));
And it works without problems... I'm using System.Urihere. Maybe you have a malformed URI or you have to use an absolute URI and use UriKind.Absoluteinstead?
它可以毫无问题地工作......我在System.Uri这里使用。也许您的 URI 格式不正确，或者您必须使用绝对 URI 并UriKind.Absolute改为使用？
回答by Jon Skeet
Well, Windows.Foundation.Uriis documented like this:
好吧，Windows.Foundation.Uri记录如下：
.NET: This type appears as System.Uri.
.NET：此类型显示为 System.Uri。
So the tricky bit isn't converting it into a Windows.Foundation.Uriyourself - it looks like WinRT does that for you. It looks like the problem is with the URI you're using. What is it relative toin this case? I suspect you really just need to find the right format for the URI.
所以棘手的一点不是将它转换成Windows.Foundation.Uri你自己 - 看起来 WinRT 为你做了。问题似乎出在您使用的 URI 上。在这种情况下，它与什么有关？我怀疑您真的只需要为 URI 找到正确的格式。
回答by walther
Try this format:
试试这个格式：
ms-appx:/Images/800x600/BackgroundTile.bmp
The given System.Uri cannot be converted into a Windows.Foundation.Uri
回答by avens19
This is what I use:
这是我使用的：
string url = "ms-appx:///Assets/placeHolder.png";
image.Source = RandomAccessStreamReference.CreateFromUri(new Uri(url));
回答by LZH
check your pictureUrl since it was what resulted in the exception.
检查您的图片网址，因为它是导致异常的原因。
but this should work as well
但这也应该有效
img.Source = new BitmapImage(new Uri(pictureUrl, UriKind.Absolute));
it should have nothing to do with Windows.Foundation.Uri. since winrt will handle it for you.
它应该与 Windows.Foundation.Uri 无关。因为 winrt 会为你处理。
回答by Scott Nimrod
This example uses a FileOpenPicker object to obtain the storage file. You can use whatever method you need to access your file as a StorageFile object.
本示例使用 FileOpenPicker 对象获取存储文件。您可以使用任何您需要的方法来访问您的文件作为 StorageFile 对象。
Logo is the name of the image control.
徽标是图像控件的名称。
Reference the following code:
参考以下代码：
var fileOpenPicker = new FileOpenPicker();
fileOpenPicker.ViewMode = PickerViewMode.Thumbnail;
fileOpenPicker.SuggestedStartLocation = PickerLocationId.PicturesLibrary;
fileOpenPicker.FileTypeFilter.Add(".png");
fileOpenPicker.FileTypeFilter.Add(".jpg");
fileOpenPicker.FileTypeFilter.Add(".jpeg");
fileOpenPicker.FileTypeFilter.Add(".bmp");
var storageFile = await fileOpenPicker.PickSingleFileAsync();
if (storageFile != null)
{
// Ensure the stream is disposed once the image is loaded
using (IRandomAccessStream fileStream = await storageFile.OpenAsync(Windows.Storage.FileAccessMode.Read))
{
// Set the image source to the selected bitmap
BitmapImage bitmapImage = new BitmapImage();
await bitmapImage.SetSourceAsync(fileStream);
Logo.Source = bitmapImage;
}
}
回答by reza.cse08
<Image Name="Img" Stretch="UniformToFill" />
var file = await KnownFolders.PicturesLibrary.GetFileAsync("2.jpg");
using(var fileStream = (await file.OpenAsync(Windows.Storage.FileAccessMode.Read))){
var bitImg= new BitmapImage();
bitImg.SetSource(fileStream);
Img.Source = bitImg;
}
