Ajax 请求中的 jQuery Ajax 请求
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jQuery Ajax Request inside Ajax Request
提问by Bias Tegaralaga
Is it possible to make an ajax request inside another ajax request? because I need some data from first ajax request to make the next ajax request.
是否可以在另一个 ajax 请求中发出 ajax 请求？因为我需要来自第一个 ajax 请求的一些数据来发出下一个 ajax 请求。
First I'm using Google Maps API to get LAT & LNG, after that I use that LAT & LNG to request Instagram API (search based location).
首先，我使用 Google Maps API 来获取 LAT 和 LNG，然后我使用 LAT 和 LNG 来请求 Instagram API（基于搜索的位置）。
Once again, is this possible, and if so how?
再一次，这是否可能，如果可能，如何？
$('input#search').click(function(e){
e.preventDefault();
var source=$('select[name=state] option:selected').text()+' '+$('select[name=city] option:selected').text()+' '+$('select[name=area] option:selected').text();
var source=source.replace(/ /g, '+');
if(working==false){
working=true;
$(this).replaceWith('<span id="big_loading"></span>');
$.ajax({
type:'POST',
url:'/killtime_local/ajax/location/maps.json',
dataType:'json',
cache: false,
data:'via=ajax&address='+source,
success:function(results){
// this is where i get the latlng
}
});
} else {
alert('please, be patient!');
}
});
回答by Tarek
Here is an example:
下面是一个例子：
$.ajax({
type: "post",
url: "ajax/example.php",
data: 'page=' + btn_page,
success: function (data) {
var a = data; // This line shows error.
$.ajax({
type: "post",
url: "example.php",
data: 'page=' + a,
success: function (data) {
}
});
}
});
回答by Nishad Up
Call second ajax from 'complete'
从“完成”调用第二个 ajax
Here is the example
这是例子
var dt='';
$.ajax({
type: "post",
url: "ajax/example.php",
data: 'page='+btn_page,
success: function(data){
dt=data;
/*Do something*/
},
complete:function(){
$.ajax({
var a=dt; // This line shows error.
type: "post",
url: "example.php",
data: 'page='+a,
success: function(data){
/*do some thing in second function*/
},
});
}
});
回答by Ved
This is just an example. You may like to customize it as per your requirement.
这只是一个例子。您可能希望根据您的要求对其进行自定义。
$.ajax({
url: 'ajax/test1.html',
success: function(data1) {
alert('Request 1 was performed.');
$.ajax({
type: 'POST',
url: url,
data: data1, //pass data1 to second request
success: successHandler, // handler if second request succeeds
dataType: dataType
});
}
});
For more details : see this
有关更多详细信息：请参阅此
回答by Yusnur Hidayah
$.ajax({
url: "<?php echo site_url('upToWeb/ajax_edit/')?>/" + id,
type: "GET",
dataType: "JSON",
success: function (data) {
if (data.web == 0) {
if (confirm('Data product upToWeb ?')) {
$.ajax({
url: "<?php echo site_url('upToWeb/set_web/')?>/" + data.id_item,
type: "post",
dataType: "json",
data: {web: 1},
success: function (respons) {
location.href = location.pathname;
},
error: function (xhr, ajaxOptions, thrownError) { // Ketika terjadi error
alert(xhr.responseText); // munculkan alert
}
});
}
}
else {
if (confirm('Data product DownFromWeb ?')) {
$.ajax({
url: "<?php echo site_url('upToWeb/set_web/')?>/" + data.id_item,
type: "post",
dataType: "json",
data: {web: 0},
success: function (respons) {
location.href = location.pathname;
},
error: function (xhr, ajaxOptions, thrownError) { // Ketika terjadi error
alert(xhr.responseText); // munculkan alert
}
});
}
}
},
error: function (jqXHR, textStatus, errorThrown) {
alert('Error get data from ajax');
}
});
