Java：如何删除两个字符串之间第一次出现的匹配子字符串？
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Java: How to Delete the first occurrence of matching substring between 2 strings?
提问by InfantPro'Aravind'
If I have two strings .. say
如果我有两个字符串..说
string1="Hello dear c'Lint and dear Bob"
and
和
string2="dear"
I want to Compare the stringsand deletethe first occurrence of matching substring ..
the result of the above string pairs is:
我想比较字符串并删除匹配子字符串的第一次出现..
上述字符串对的结果是：
Hello c'Lint and dear Bob
Hello c'Lint and dear Bob
This is the code I have written which takes input and returns the matching occurence:
这是我编写的代码，它接受输入并返回匹配的出现：
System.out.println("Enter your regex: ");
BufferedReader bufferRead = new BufferedReader(new InputStreamReader(System.in));
String RegEx = bufferRead.readLine();
Pattern pattern = Pattern.compile(RegEx);
System.out.println("Enter input string to search: ");
bufferRead = new BufferedReader(new InputStreamReader(System.in));
Matcher matcher = pattern.matcher(bufferRead.readLine());
boolean found = false;
while (matcher.find()) {
System.out.println("I found the text:\"" + matcher.group() +
"\" starting at index \'" +
matcher.start() +
"\' and ending at index \'" +
matcher.end() +
"\'");
}
回答by Jon Skeet
You could eitheruse:
你可以任意使用：
string result = string1.replaceFirst(Pattern.quote(string2), "");
Or you could avoid regexes entirely:
或者您可以完全避免使用正则表达式：
int index = string1.indexOf(string2);
if (index == -1)
{
// Not found. What do you want to do?
}
else
{
String result = string1.substring(0, index) +
string1.substring(index + string2.length());
}
You can report the region here using indexand string2.length()very easily. Of course if you wantto be able to match regular expression patterns, you should use them.
您可以在此处使用index和string2.length()非常轻松地报告区域。当然，如果您希望能够匹配正则表达式模式，则应该使用它们。
EDIT: As noted in another answer, both of these will remove "dear"from "and_dear_Bob"leaving "and__Bob"- with the underscores representing spaces. So you'll end up with two spaces between words. And it doesn't force the match to be a whole word, either. It does exactly what you described, but it doesn't give you the result you apparently want.
编辑：如另一个答案中所述，这两个都"dear"将从"and_dear_Bob"离开中删除"and__Bob"- 下划线代表空格。所以你最终会在单词之间有两个空格。它也不会强制匹配是一个完整的词。它完全符合您的描述，但它没有给您显然想要的结果。
Edit:First choice of code outputs: Hello c'Lint and dear Bobwhere Hello and c'Lint have two whitespace character in the middle.
While this code:
编辑：代码输出的首选：Hello c'Lint and dear Bob其中 Hello 和 c'Lint 中间有两个空格字符。虽然这段代码：
string result = string1.replaceFirst(Pattern.quote(string2+" "), ""));
gets rid of additional whitespace character.
摆脱额外的空白字符。
