PHP 函数获取 URL 的子域
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PHP function to get the subdomain of a URL
提问by Damiano
Is there a function in PHP to get the name of the subdomain?
PHP中是否有获取子域名称的函数？
In the following example I would like to get the "en" part of the URL:
在以下示例中，我想获取 URL 的“en”部分：
en.example.com
回答by Michael Deal
Here's a one line solution:
这是一个单行解决方案：
array_shift((explode('.', $_SERVER['HTTP_HOST'])));
Or using your example:
或使用您的示例：
array_shift((explode('.', 'en.example.com')));
EDIT: Fixed "only variables should be passed by reference" by adding double parenthesis.
编辑：通过添加双括号修复“仅变量应通过引用传递”。
EDIT 2: Starting from PHP 5.4you can simply do:
编辑 2：从PHP 5.4开始，您可以简单地执行以下操作：
explode('.', 'en.example.com')[0];
回答by Mike Lewis
Uses the parse_urlfunction.
使用parse_url函数。
$url = 'http://en.example.com';
$parsedUrl = parse_url($url);
$host = explode('.', $parsedUrl['host']);
$subdomain = $host[0];
echo $subdomain;
For multiple subdomains
对于多个子域
$url = 'http://usa.en.example.com';
$parsedUrl = parse_url($url);
$host = explode('.', $parsedUrl['host']);
$subdomains = array_slice($host, 0, count($host) - 2 );
print_r($subdomains);
回答by mazon
You can do this by first getting the domain name (e.g. sub.example.com => example.co.uk) and then use strstr to get the subdomains.
您可以通过首先获取域名（例如 sub.example.com => example.co.uk）然后使用 strstr 获取子域来完成此操作。
$testArray = array(
'sub1.sub2.example.co.uk',
'sub1.example.com',
'example.com',
'sub1.sub2.sub3.example.co.uk',
'sub1.sub2.sub3.example.com',
'sub1.sub2.example.com'
);
foreach($testArray as $k => $v)
{
echo $k." => ".extract_subdomains($v)."\n";
}
function extract_domain($domain)
{
if(preg_match("/(?P<domain>[a-z0-9][a-z0-9\-]{1,63}\.[a-z\.]{2,6})$/i", $domain, $matches))
{
return $matches['domain'];
} else {
return $domain;
}
}
function extract_subdomains($domain)
{
$subdomains = $domain;
$domain = extract_domain($subdomains);
$subdomains = rtrim(strstr($subdomains, $domain, true), '.');
return $subdomains;
}
Outputs:
输出：
0 => sub1.sub2
1 => sub1
2 =>
3 => sub1.sub2.sub3
4 => sub1.sub2.sub3
5 => sub1.sub2
回答by JMW
<?php
$url = 'http://user:[email protected]/path?argument=value#anchor';
$array=parse_url($url);
$array['host']=explode('.', $array['host']);
echo $array['host'][0]; // returns 'en'
?>
回答by Sascha Frinken
As the only reliable source for domain suffixes are the domain registrars, you can't find the subdomain without their knowledge. There is a list with all domain suffixes at https://publicsuffix.org. This site also links to a PHP library: https://github.com/jeremykendall/php-domain-parser.
由于域后缀的唯一可靠来源是域注册商，因此您无法在他们不知情的情况下找到子域。https://publicsuffix.org 上有一个包含所有域后缀的列表。该站点还链接到一个 PHP 库：https: //github.com/jeremykendall/php-domain-parser。
Please find an example below. I also added the sample for en.test.co.uk which is a domain with a multi suffix (co.uk).
请在下面找到一个例子。我还添加了 en.test.co.uk 的示例，这是一个带有多后缀 (co.uk) 的域。
<?php
require_once 'vendor/autoload.php';
$pslManager = new Pdp\PublicSuffixListManager();
$parser = new Pdp\Parser($pslManager->getList());
$host = 'http://en.example.com';
$url = $parser->parseUrl($host);
echo $url->host->subdomain;
$host = 'http://en.test.co.uk';
$url = $parser->parseUrl($host);
echo $url->host->subdomain;
回答by Arjen
Simplest and fastest solution.
最简单和最快的解决方案。
$sSubDomain = str_replace('.example.com','',$_SERVER['HTTP_HOST']);
回答by Kamafeather
Simply...
简单地...
preg_match('/(?:http[s]*\:\/\/)*(.*?)\.(?=[^\/]*\..{2,5})/i', $url, $match);
Just read $match[1]
只需阅读$match[1]
Working example
工作示例
It works perfectly with this list of urls
它与此网址列表完美配合
$url = array(
'http://www.domain.com', // www
'http://domain.com', // --nothing--
'https://domain.com', // --nothing--
'www.domain.com', // www
'domain.com', // --nothing--
'www.domain.com/some/path', // www
'http://sub.domain.com/domain.com', // sub
'опубликованному.значения.ua', // опубликованному ;)
'значения.ua', // --nothing--
'http://sub-domain.domain.net/domain.net', // sub-domain
'sub-domain.third-Level_DomaIN.domain.uk.co/domain.net' // sub-domain
);
foreach ($url as $u) {
preg_match('/(?:http[s]*\:\/\/)*(.*?)\.(?=[^\/]*\..{2,5})/i', $u, $match);
var_dump($match);
}
回答by Jared Farrish
$REFERRER = $_SERVER['HTTP_REFERER']; // Or other method to get a URL for decomposition
$domain = substr($REFERRER, strpos($REFERRER, '://')+3);
$domain = substr($domain, 0, strpos($domain, '/'));
// This line will return 'en' of 'en.example.com'
$subdomain = substr($domain, 0, strpos($domain, '.'));
回答by Jeacovy Gayle
PHP 7.0: Using the explode function and create a list of all the results.
PHP 7.0：使用爆炸函数并创建所有结果的列表。
list($subdomain,$host) = explode('.', $_SERVER["SERVER_NAME"]);
Example: sub.domain.com
示例：sub.domain.com
echo $subdomain;
Result: sub
结果：子
echo $host;
Result: domain
结果：域
回答by Jeacovy Gayle
$domain = 'sub.dev.example.com';
$tmp = explode('.', $domain); // split into parts
$subdomain = current($tmp);
print($subdomain); // prints "sub"
As seen in a previous question: How to get the first subdomain with PHP?
如上一个问题所示： How to get the first subdomain with PHP?
