PHP：根据 $value 更改文本颜色
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PHP: Change color of text based on $value
提问by Kevin Brown
What's the easiest way to change a text's color based on a variable?
根据变量更改文本颜色的最简单方法是什么？
For example: If $var is between 1-5, green. Between 6-10, Orange. Greater than 11, Red.
例如：如果 $var 介于 1-5 之间，则为绿色。6-10 之间，橙色。大于 11，红色。
采纳答案by Kevin Brown
回答by sshow
function getProperColor($number)
{
if ($var > 0 && $var <= 5)
return '#00FF00';
else if ($var >= 6 && $var <= 10)
return = '#FF8000';
else if ($var >= 11)
return = '#FF0000';
}
And use it like this
并像这样使用它
<div style="background-color: <?=getProperColor($result['number'])?>;"><?=$result["title"]?></div>
回答by LukeN
$color = "#000000";
if (($v >= 1) && ($v <= 5))
$color = "#00FF00";
else if (($v >= 6) && ($v <= 10))
$color = "#FF9900";
else if ($v >= 11)
$color = "#FF0000";
echo "<span style=\"color: $color\">Text</span>";
回答by doc
Are color values indexed by constants? I would prepare hash map
颜色值是否由常量索引？我会准备哈希图
$colorMap[0] = '#00FF00'; //green
$colorMap[1] = '#0000FF'; //blue
$colorMap[2] = '#FF0000'; //red
$colorMap[3] = '#330000'; //dark red
and so on. Then use CSS
等等。然后使用CSS
<span style="color: <?php echo $colorMap[$var]; ?>;">desired color</span>
回答by zaf
I'll use CSS colors and also highlight the fact that the number 11 does not map to any color according to your rules making most of the answers invalid :)
我将使用 CSS 颜色并强调数字 11 不会根据您的规则映射到任何颜色的事实，这使得大多数答案无效:)
<?php
$color=getColor(11);
function getColor($n){
// Is number between 1 and 5?
if($n>=1 && $n<=5) return "green";
// Is number between 6 and 10?
if($n>=6 && $n<=10) return "orange";
// Is number greater than 11
if($n>11) return "red";
// Return default (black) for all other numbers
return "black";
}
?>
<span style='color:<?=$color?>'>Text</span>
回答by fafnirbcrow
You need to actually use elseif statements if your going to use a set of if statements,
如果要使用一组 if 语句，则需要实际使用 elseif 语句，
if ($var < 6) $color = '#00FF00';
elseif ($var < 10) $color = '#FF8000';
elseif ($var > 10) $color = '#FF0000';
回答by JYelton
Something like this trio of if statements:
类似于这三个 if 语句：
if ($var < 10) $color = '#FF8000';
if ($var < 6) $color = '#00FF00';
if ($var >= 10) $color = '#FF0000';
echo "<span style=\"color: $color;\">This text is colored.</span>";
回答by Rik Heywood
A simple solution might be to do something like this...
一个简单的解决方案可能是做这样的事情......
if ($var < 6)
$style="0F0";
else if ($var < 11)
$style="F50";
else
$style = "F00";
?><div style="color:#<?php echo $style; ?>">blar</div>
回答by alexganose
Ternary operator for your simple example.
简单示例的三元运算符。
$color = ($var < 6) ? '#FF8000' : (($var < 10) ? '#00FF00' : '#FF0000');
回答by Finzzownt
Assuming one works with ranges than this is quite flexible:
假设一个工作范围比这非常灵活：
function getProperColor($range, $value)
{
foreach($range as $key => $color)
{
if ($value <= $key)
return $color;
}
return $color;
}
$colorRange = array(
5 => 'green',
10 => 'orange',
11 => 'red'
);
for($i=-1;$i<16;$i+=2)
{
echo "$i:" . getProperColor($colorRange, $i) . "\n";
}
This will output:
这将输出：
-1:green
1:green
3:green
5:green
7:orange
9:orange
11:red
13:red
15:red
