bash 正则表达式中的AWK行尾符号
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AWK end of line sign in regular expressions
提问by Mikhail Kalashnikov
I have a simple awk script named "script.awk" that contains:
我有一个名为“script.awk”的简单 awk 脚本，其中包含：
/\/some_simple_string/ { print 14 catcat one_two/some_thing
15 catcat one_three/one_more_some_simple_string
16 dogdog one_two/some_simple_string_again
17 dogdog one_four/some_simple_string
18 qweqwe firefire/ppp
;}
I'm using it to parse some file that contains: (by using: cat file | awk -f script.awk)
我正在使用它来解析一些包含以下内容的文件：（通过使用：cat file | awk -f script.awk）
17 dogdog one_four/some_simple_string
I want the script to only print the stroke that fully reflect "/some_simple_string[END_OF_LINE]" but not 2 or 3. Is there any simple way to do it?
我希望脚本只打印完全反映“/some_simple_string[END_OF_LINE]”的笔画，而不是 2 或 3。有什么简单的方法可以做到？
I think, the most appropriate way is to add end-of-line sigh to the regular expression. So it will parse only strokes that starting with "/some.." and have a new line at the end of "..string[END_OF_LINE]"
我认为，最合适的方法是在正则表达式中添加行尾叹气。所以它只会解析以“/some..”开头的笔画，并在“..string[END_OF_LINE]”的末尾有一个新行
Desired output:
期望的输出：
/\/some_simple_string$/ { print /\/some_simple_string$/ { print /some_simple_string/ { x = $ grep '/some_simple_string$' file
}
END{ print x }
}
;}
Sorry for confusion, I was asking for END OF LINE sign in regular expressions. The correct answer is:
抱歉造成混淆，我要求在正则表达式中使用 END OF LINE 符号。正确答案是：
$ awk '/[/]some_simple_string$/' file
回答by Alderath
You can always use:
您可以随时使用：
$ awk 'print_flag{print;f=0} /[/]some_simple_string$/{print_flag=1}' file
I.e. match not only "some_simple_string" but match "/some_simple_string" followed by the end of the line ($ is end of line in regex)
即不仅匹配“some_simple_string”而且匹配“/some_simple_string”后跟行尾（$是正则表达式中的行尾）
回答by lc2817
grep '\some_simple_string$' file | tail -n 1should do the trick.
grep '\some_simple_string$' file | tail -n 1应该做的伎俩。
Or if you really want to use awkdo awk '/\/some_simple_string/{x = $0}END{print x}'
或者如果你真的想使用awkdoawk '/\/some_simple_string/{x = $0}END{print x}'
回答by luser droog
To return just the lastof a group of matches, ...
要仅返回一组匹配项中的最后一个，...
Store the line in a variable and print it in the ENDblock.
将该行存储在变量中并将其打印在END块中。
$ grep -A1 '/some_simple_string$' file | tail -n 1
回答by Chris Seymour
To print all the matches that end with the string /some_simple_stringusing regular expression you need to anchor to the the end of the line using $. The most suitable tool for this job is grep:
要/some_simple_string使用正则表达式打印以字符串结尾的所有匹配项，您需要使用$. 最适合这项工作的工具是grep：
In awkthe command is much the same:
在awk命令中大致相同：
To print all lines after the matching you would do:
要在匹配后打印所有行，您可以执行以下操作：
##代码##Or just combine grepand tailif it makes it clearer using context option -Ato print the following lines:
或者只是组合grep，tail如果使用上下文选项-A打印以下行使其更清晰：
