java 如何在 REST 响应后删除文件
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How to delete file after REST response
提问by tarka
What is the best way to handle deleting a file after it has been returned as the response to a REST request?
在文件作为对 REST 请求的响应返回后处理删除文件的最佳方法是什么？
I have an endpoint that creates a file on request and returns it in the response. Once the response has been dispatched the file is no longer needed and can/should be removed.
我有一个端点，它根据请求创建一个文件并在响应中返回它。一旦响应被分派，文件就不再需要并且可以/应该被删除。
@Path("file")
@GET
@Produces({MediaType.APPLICATION_OCTET_STREAM})
@Override
public Response getFile() {
// Create the file
...
// Get the file as a steam for the entity
File file = new File("the_new_file");
ResponseBuilder response = Response.ok((Object) file);
response.header("Content-Disposition", "attachment; filename=\"the_new_file\"");
return response.build();
// Obviously I can't do this but at this point I need to delete the file!
}
I guess I could create a tmp file but I would have thought there was a more elegant mechanism to achieve this. The file could be quite large so I cannot load it into memory.
我想我可以创建一个 tmp 文件，但我认为有一个更优雅的机制来实现这一点。该文件可能很大，因此我无法将其加载到内存中。
采纳答案by cmaulini
There is a more elegant solution, don't write a file, just write directly to the output stream contained in the instance of Response.
有一个更优雅的解决方案，不写文件，直接写到包含在实例中的输出流Response。
回答by cmaulini
Use a StreamingOutput as entity:
使用 StreamingOutput 作为实体：
final Path path;
...
return Response.ok().entity(new StreamingOutput() {
@Override
public void write(final OutputStream output) throws IOException, WebApplicationException {
try {
Files.copy(path, output);
} finally {
Files.delete(path);
}
}
}
回答by sinclair
Without knowing the context of your application, you can delete the file when the VM exits:
在不知道应用程序上下文的情况下，您可以在 VM 退出时删除该文件：
file.deleteOnExit();
See: https://docs.oracle.com/javase/7/docs/api/java/io/File.html#deleteOnExit%28%29
请参阅：https: //docs.oracle.com/javase/7/docs/api/java/io/File.html#deleteOnExit%28%29
回答by Praneeth
I did something like this recently in rest service development using jersey
我最近在使用 jersey 的休息服务开发中做了类似的事情
@GET
@Produces("application/zip")
@Path("/export")
public Response exportRuleSet(@QueryParam("ids") final List<String> ids) {
try {
final File exportFile = serviceClass.method(ruleSetIds);
final InputStream responseStream = new FileInputStream(exportFile);
StreamingOutput output = new StreamingOutput() {
@Override
public void write(OutputStream out) throws IOException, WebApplicationException {
int length;
byte[] buffer = new byte[1024];
while((length = responseStream.read(buffer)) != -1) {
out.write(buffer, 0, length);
}
out.flush();
responseStream.close();
boolean isDeleted = exportFile.delete();
log.info(exportFile.getCanonicalPath()+":File is deleted:"+ isDeleted);
}
};
return Response.ok(output).header("Content-Disposition", "attachment; filename=rulset-" + exportFile.getName()).build();
}
回答by silentCode
save the response in a tmp variable with replacing your return statement like this:
将响应保存在 tmp 变量中，并像这样替换 return 语句：
Response res = response.build();
//DELETE your files here.
//maybe this is not the best way, at least it is a way.
return res;
回答by Abdelkader
send file name on response:
响应时发送文件名：
return response.header("filetodelete", FILE_OUT_PUT).build();
after that you can send delete restful method
之后你可以发送删除restful方法
@POST
@Path("delete/{file}")
@Produces(MediaType.TEXT_PLAIN)
public void delete(@PathParam("file") String file) {
File delete = new File(file);
delete.delete();
}
