PHP 从字符串中删除特殊字符
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PHP remove special character from string
提问by user453089
I have problems with removing special characters. I want to remove all special characters except "( ) / . % - &", because I'm setting that string as a title.
我在删除特殊字符时遇到问题。我想删除除“( ) / . % - &”之外的所有特殊字符，因为我将该字符串设置为标题。
I edited code from the original (look below):
我编辑了原始代码（请看下面）：
preg_replace('/[^a-zA-Z0-9_ -%][().][\/]/s', '', $String);
But this is not working to remove special characters like: "a?s, "a?", "a", among others.
但这并不能删除特殊字符，例如：“a?s、“a?”、“a”等。
original code: (this works but it removes these characters: "( ) / . % - &")
原始代码：（这有效，但它删除了这些字符：“( ) / . % - &”）
preg_replace('/[^a-zA-Z0-9_ -]/s', '', $String);
回答by Luke Sneeringer
Your dot is matching all characters. Escape it (and the other special characters), like this:
您的点匹配所有字符。转义它（和其他特殊字符），如下所示：
preg_replace('/[^a-zA-Z0-9_ %\[\]\.\(\)%&-]/s', '', $String);
回答by Thomas Hupkens
preg_replace('#[^\w()/.%\-&]#',"",$string);
回答by Anonymoose
Good try! I think you just have to make a few small changes:
很好的尝试！我认为你只需要做一些小的改变：
- Escape the square brackets (
[and]) inside the character class (which are also indicated by[and]) - Escape the escape character (
\) itself - Plus there's a quirk where
-is special: if it's between two characters, it means a range, but if it's at the beginning or the end, it means the literal-character.
- 转义字符类中的方括号（
[和]）（也由[和表示]） - 转义转义字符 (
\) 本身 - 另外还有一个
-特殊之处：如果它在两个字符之间，则表示范围，但如果它在开头或结尾，则表示文字-字符。
You'll want something like this:
你会想要这样的东西：
preg_replace('/[^a-zA-Z0-9_%\[().\]\/-]/s', '', $String);
See http://docs.activestate.com/activeperl/5.10/lib/pods/perlrecharclass.html#special_characters_inside_a_bracketed_character_classif you want to read up further on this topic.
如果您想进一步阅读此主题，请参阅http://docs.activestate.com/activeperl/5.10/lib/pods/perlrecharclass.html#special_characters_inside_a_bracketed_character_class。
回答by Frank Nocke
You want str replace, because performance-wise it's muchcheaper and still fits your needs!
你希望海峡更换，因为性能方面它是多便宜，仍然适合您的需要！
$title = str_replace( array( '\'', '"', ',' , ';', '<', '>' ), ' ', $rawtitle);
(Unless this is all about security and sql injection, in that case, I'd rather to go with a POSITIVE list of ALLOWED characters... even better, stick with tested, proven routines.)
（除非这完全是关于安全性和 sql 注入，在这种情况下，我宁愿使用 ALLOWED 字符的 POSITIVE 列表......更好的是，坚持使用经过测试的、经过验证的例程。）
Btw, since the OP talked about title-setting: I wouldn't replace special chars with nothing, but with a space. A superficious space is less of a problem than two words glued together...
顺便说一句，由于 OP 谈到了标题设置：我不会用任何东西替换特殊字符，而是用空格替换。一个肤浅的空间比两个词粘在一起更不是问题......
回答by dinhhiepdung
<?php
$string = '`~!@#$%^&^&*()_+{}[]|\/;:"< >,.?-<h1>You .</h1><p> text</p>'."'";
$string=strip_tags($string,"");
$string = preg_replace('/[^A-Za-z0-9\s.\s-]/','',$string);
echo $string = str_replace( array( '-', '.' ), '', $string);
?>
回答by Alex
preg_replace('/[^a-zA-Z0-9_ \-()\/%-&]/s', '', $String);
回答by TechyFlick
mysqli_set_charset($con,"utf8");
$title = ' LEVEL a“ EXTENDED';
$newtitle = preg_replace('/[^(\x20-\x7F)]*/','', $title);
echo $newtitle;
Result : LEVEL EXTENDED
Many Strange Character be removed by applying below the mysql connection code. but in some circumstances of removing this type strange character like a you can use preg_replace above format.
通过在mysql连接代码下方应用，可以删除许多奇怪的字符。但是在某些情况下，您可以使用 preg_replace 上面的格式删除这种类型的奇怪字符。
回答by binkute
See example.
参见示例。
/**
* nv_get_plaintext()
*
* @param mixed $string
* @return
*/
function nv_get_plaintext( $string, $keep_image = false, $keep_link = false )
{
// Get image tags
if( $keep_image )
{
if( preg_match_all( "/\<img[^\>]*src=\"([^\"]*)\"[^\>]*\>/is", $string, $match ) )
{
foreach( $match[0] as $key => $_m )
{
$textimg = '';
if( strpos( $match[1][$key], 'data:image/png;base64' ) === false )
{
$textimg = " " . $match[1][$key];
}
if( preg_match_all( "/\<img[^\>]*alt=\"([^\"]+)\"[^\>]*\>/is", $_m, $m_alt ) )
{
$textimg .= " " . $m_alt[1][0];
}
$string = str_replace( $_m, $textimg, $string );
}
}
}
// Get link tags
if( $keep_link )
{
if( preg_match_all( "/\<a[^\>]*href=\"([^\"]+)\"[^\>]*\>(.*)\<\/a\>/isU", $string, $match ) )
{
foreach( $match[0] as $key => $_m )
{
$string = str_replace( $_m, $match[1][$key] . " " . $match[2][$key], $string );
}
}
}
$string = str_replace( '?', ' ', strip_tags( $string ) );
return preg_replace( '/[ ]+/', ' ', $string );
}
