xcode 你能在objective-c中返回两个参数吗？
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Can you return two arguments in objective-c?
提问by nickthedude
Just wondering if you can return two arguments in an objective c method, for example I'd like to return a cartesian coordinate (x,y), basically two ints. is the only way to do this by creating a class and returning an instance? Is there some other way I'm not thinking of, kind of a beginner here.
只是想知道是否可以在客观 c 方法中返回两个参数，例如我想返回笛卡尔坐标 (x,y)，基本上是两个整数。是通过创建一个类并返回一个实例来做到这一点的唯一方法吗？有没有我没有想到的其他方式，这里是初学者。
(Syntactical help would also be appreciated.)
（语法帮助也将不胜感激。）
Thanks,
谢谢，
Nick
缺口
回答by gavinb
You can only return one value from a function (just like C), but the value can be anything, including a struct. And since you can return a struct by value, you can define a function like this (to borrow your example):
您只能从函数中返回一个值（就像 C 语言一样），但该值可以是任何东西，包括结构体。并且由于您可以按值返回结构，因此您可以定义这样的函数（借用您的示例）：
-(NSPoint)scalePoint:(NSPoint)pt by:(float)scale
{
return NSMakePoint(pt.x*scale, pt.y*scale);
}
This is only really appropriate for small/simple structs.
这仅适用于小/简单结构。
If you want to return more than one new object, your function should take pointers to the object pointer, thus:
如果你想返回一个以上的新对象，你的函数应该采用指向对象指针的指针，因此：
-(void)mungeFirst:(NSString**)stringOne andSecond:(NSString**)stringTwo
{
*stringOne = [NSString stringWithString:@"foo"];
*stringTwo = [NSString stringWithString:@"baz"];
}
回答by Chris Long
Couldn't you make an NSArrayfor this?
你不能NSArray为此做一个吗？
return [NSArray arrayWithObjects:coorX, coorY, nil];
回答by Chuck
You can either return one value directly and return another by reference, as shown in gs's answer, or create a struct type and return that. For example, Cocoa already includes a type to identify points on a 2D plane, NSPoint.
您可以直接返回一个值并通过引用返回另一个值，如gs's answer所示，或者创建一个结构类型并返回它。例如，Cocoa 已经包含一个类型来识别 2D 平面上的点，NSPoint。
回答by Jeba Moses
I recommend you to return an NSDictionary, inside Dictionary you can store and send any object type and any number of variables.
我建议您返回一个 NSDictionary，在 Dictionary 中您可以存储和发送任何对象类型和任意数量的变量。
-(NSDictionary*)calculateWith:(id)arg
{
NSDictionary *urDictionary =@{@"key1":value1,@"Key2":value2,.....};
return urDictionary;
}
