java 将字符串转换为字符并按降序排序（ascii）
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Converting string to char and sort in descending order (ascii)
提问by kix
I am creating a program which will make the user input integer (one after another), stored in array and display the integers in descending order. The program also ask to the user to input a string convert it to char using string.toCharArray(). I've correctly done displaying the integer into descending order. The problem is I don't know how to display the char descendingly.
我正在创建一个程序，它将使用户输入整数（一个接一个），存储在数组中并按降序显示整数。该程序还要求用户输入一个字符串，使用string.toCharArray(). 我已经正确地将整数显示为降序。问题是我不知道如何降序显示字符。
This is the code for the integer:
这是整数的代码：
for(i=0;i<nums.length;i++){
System.out.print("Enter value for index["+i+"] here --> ");
nums[i]=Integer.parseInt(br.readLine());}
while(pass<nums.length){
for(i=0;i<(nums.length-pass);i++){
if(nums[i]<nums[i+1]){
temp=nums[i];
nums[i]=nums[i+1];
nums[i+1]=temp;
}
}
pass++;
}
System.out.println("\n\nThe numbers when sorted descendingly are :\n");
for(i=0;i<nums.length;i++){
System.out.println(nums[i]);
This is the code for the string to array. This is where i'm having problems. I don't have errors in running the program just it's just I don't how to do it correctly.
这是要数组的字符串的代码。这是我遇到问题的地方。我在运行程序时没有错误，只是我不知道如何正确执行。
System.out.print("Input a string");
String strValue= br.readLine();
char[] chrValues;
chrValues=strValue.toCharArray( );
while(flag<chrValues.length){
for (c=0; c< (chrValues.length- flag); c++){
if(chrValues[c]<chrValues[i+1]){
tempo=chrValues[c];
chrValues[c]=chrValues[c+1];
chrValues[c+1]= tempo;}
}
}
flag++;
System.out.println("\n\nThe String when converted in character and sorted descendingly are :\n");
for(c=0;i<chrValues.length;c++){
System.out.println(chrValues[c]);}
By the way, I used flag as a temporary array storage.
顺便说一句，我使用 flag 作为临时数组存储。
采纳答案by Peter Lawrey
You can try
你可以试试
String str = "AbCdEf";
char[] arr = str.toCharArray();
for(int i = 0; i < arr.length; i++) System.out.print(arr[i]);
System.out.println();
Arrays.sort(arr); // sorted in ascending order
// print them backwards i.e. descending order.
for(int i = arr.length - 1; i >= 0; i--) System.out.print(arr[i]);
System.out.println();
prints
印刷
AbCdEf
fdbECA
回答by Rohit Jain
You already have built-in method for that: -
你已经有内置的方法： -
String str = "Rohit";
char[] arr = str.toCharArray();
System.out.println(arr);
Arrays.sort(arr); // Sort in Ascending order
System.out.println(arr);
For descending order, you can define a Comparatorand pass that to Arrays.sort()method..
对于降序，您可以定义 aComparator并将其传递给Arrays.sort()方法..
You can use Arrays#sortand ArrayUtils#toObjectfor sorting in Descending order..
您可以使用Arrays#sort和ArrayUtils#toObject在Descending order..
Here's how it works: -
这是它的工作原理： -
String str = "Rohit";
char[] charArray = str.toCharArray();
Character[] myCharArr = ArrayUtils.toObject(charArray);
Arrays.sort(myCharArr, new Comparator<Character>() {
@Override
public int compare(Character char1, Character char2) {
return char2.compareTo(char1);
}
});
for (char val: myCharArr) {
System.out.print(val);
}
