如何简单地比较 C++ 中的字符？
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How do I simply compare characters in C++?
提问by Dmitriy Potemkin
I have the following code:
我有以下代码：
#include <iostream>
using namespace std;
int main()
{
char fg;
cin>>fg;
char x[20];
x[0]='0';
if(fg=x[0])
{
cout<<"It's true!"<<endl;
return true;
}
cout<<"It's false!"<<endl;
return false;
}
No matter what input I give, trueis always returned. Is my syntax off? Any help would be appreciated.
无论我给出什么输入，true总是返回。我的语法关闭了吗？任何帮助，将不胜感激。
回答by dasblinkenlight
In C++ you use ==for comparison. The =is an assignment. It can be used in the condition of an ifstatement, but it's going to evaluate to trueunless the character is '\0'(not '0', as it is in your case):
在 C++ 中，您==用于比较。这=是一个任务。它可以在if语句的条件中使用，但true除非字符是'\0'（不是'0'，就像你的情况一样），否则它将被评估为：
if(fg == x[0])
{
...
}
回答by Rijesh4
Within if statement use ==. For Eg:
在 if 语句中使用==。例如：
if (fg == x[0]) {
//...........
}
==compares, but =makes fgequal to x[0], and that's why you get true every time.
==相比较，但=品牌fg等于x[0]，这就是为什么你每次都获得正确的。
