C# 如何在代码中编写 JSON 字符串值？
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How to write JSON string value in code?
提问by user1811801
I want to store the following string in a String variable
我想将以下字符串存储在 String 变量中
{"Id":"123","DateOfRegistration":"2012-10-21T00:00:00+05:30","Status":0}
{"Id":"123","DateOfRegistration":"2012-10-21T00:00:00+05:30","Status":0}
This is the code I use ..
这是我使用的代码..
String str="{"Id":"123","DateOfRegistration":"2012-10-21T00:00:00+05:30","Status":0}";
.. but it's showing error ..
.. 但它显示错误..
采纳答案by Freak
You have to do this
你必须这样做
String str="{\"Id\":\"123\",\"DateOfRegistration\":\"2012-10-21T00:00:00+05:30\",\"Status\":0}";
Please see this for reference
Also from msdn :)
Short Notation UTF-16 character Description
\' \u0027 allow to enter a ' in a character literal, e.g. '\''
\" \u0022 allow to enter a " in a string literal, e.g. "this is the double quote (\") character"
\ \u005c allow to enter a \ character in a character or string literal, e.g. '\' or "this is the backslash (\) character"
String str="{\"Id\":\"123\",\"DateOfRegistration\":\"2012-10-21T00:00:00+05:30\",\"Status\":0}";
\u0000 allow to enter the character with code 0
\a \u0007 alarm (usually the HW beep)
\b \u0008 back-space
\f \u000c form-feed (next page)
\n \u000a line-feed (next line)
\r \u000d carriage-return (move to the beginning of the line)
\t \u0009 (horizontal-) tab
\v \u000b vertical-tab
回答by Basti M
You have to escape the quotes within the string like this:
您必须像这样转义字符串中的引号：
String str="{\"Id\":\"123\",\"DateOfRegistration\":\"2012-10-21T00:00:00+05:30\",\"Status\":0}";
回答by Brian
you need to escape the inner quotes like so:
你需要像这样转义内部引号：
string str = "{'Id':'123','DateOfRegistration':'2012 - 10 - 21T00: 00:00 + 05:30','Status':0}".Replace("'", "\"");
回答by Mohammad Nikravan
I prefer this, just make sure you don't have single quote in the string
我更喜欢这个，只要确保字符串中没有单引号
dynamic contact = new ExpandoObject();
contact.Name = “Patrick Hines”;
contact.Phone = “206-555-0144”;
contact.Address = new ExpandoObject();
contact.Address.Street = “123 Main St”;
contact.Address.City = “Mercer Island”;
contact.Address.State = “WA”;
contact.Address.Postal = “68402”;
//Serialize to get Json string using NewtonSoft.JSON
string Json = JsonConvert.SerializeObject(contact);
回答by sudhAnsu63
There is an alternate way to write these complex JSON using Expando object or XElement and then serialize.
有一种替代方法可以使用 Expando 对象或 XElement 编写这些复杂的 JSON，然后进行序列化。
##代码##