ios Swift 读取远程通知的 userInfo

Swift read userInfo of remote notification

提问by F3rret

I implemented a function to open an AlertView when I receive a remote notification like this:

当我收到这样的远程通知时，我实现了一个打开 AlertView 的功能：

func application(application: UIApplication, didReceiveRemoteNotification userInfo: [NSObject : AnyObject]){
        var notifiAlert = UIAlertView()
        var NotificationMessage : AnyObject? =  userInfo["alert"]
        notifiAlert.title = "TITLE"
        notifiAlert.message = NotificationMessage as? String
        notifiAlert.addButtonWithTitle("OK")
        notifiAlert.show()
}

But NotificationMessage is always nil.

但是 NotificationMessage 始终为零。

My json payload looks like this:

我的 json 有效负载如下所示：

{"aps":{"alert":"Testmessage","badge":"1"}}

I am using Xcode 6, Swift and I am developing for iOS8. I searched hours now, but didn't find any useful information. The Notifications works perfectly.. and if I click it, the alertview opens. My problem is, that I am not able to get the data out of userInfo.

我正在使用 Xcode 6、Swift 并且正在为 iOS8 进行开发。我现在搜索了几个小时，但没有找到任何有用的信息。通知工作完美......如果我点击它，警报视图会打开。我的问题是，我无法从 userInfo 中获取数据。

回答by Craig Stanford

The root level item of the userInfodictionary is "aps", not "alert".

userInfo字典的根级别项目是"aps"，不是"alert"。

Try the following:

请尝试以下操作：

if let aps = userInfo["aps"] as? NSDictionary {
    if let alert = aps["alert"] as? NSDictionary {
        if let message = alert["message"] as? NSString {
           //Do stuff
        }
    } else if let alert = aps["alert"] as? NSString {
        //Do stuff
    }
}

See Push Notification Documentation

请参阅推送通知文档

回答by Ming Chu

Method (Swift 4):

方法（Swift 4）：

func extractUserInfo(userInfo: [AnyHashable : Any]) -> (title: String, body: String) {
    var info = (title: "", body: "")
    guard let aps = userInfo["aps"] as? [String: Any] else { return info }
    guard let alert = aps["alert"] as? [String: Any] else { return info }
    let title = alert["title"] as? String ?? ""
    let body = alert["body"] as? String ?? ""
    info = (title: title, body: body)
    return info
}

Usage:

用法：

let info = self.extractUserInfo(userInfo: userInfo)
print(info.title)
print(info.body)

回答by BLC

For me, when I send the message from Accengage, the following code works -

对我来说，当我从Accengage发送消息时，以下代码有效 -

private func extractMessage(fromPushNotificationUserInfo userInfo:[NSObject: AnyObject]) -> String? {
    var message: String?
    if let aps = userInfo["aps"] as? NSDictionary {
        if let alert = aps["alert"] as? NSDictionary {
            if let alertMessage = alert["body"] as? String {
                message = alertMessage              
            }
        }
    }
    return message
}

The only difference from Craing Stanford's answer is the keyI used to extract message from alertinstance which is bodywhich is different. See below for more clearification -

与 Craing Stanford's answer 的唯一区别是keyI used to extract message from alertinstance which is bodywhich is different。请参阅下文了解更多信息 -

if let alertMessage = alert["message"] as? NSString

vs

对比

if let alertMessage = alert["body"] as? String

回答by jaiswal Rajan

Alert should be showing while the app is in active state. So check the state is active or not.

当应用程序处于活动状态时，应显示警报。因此，请检查状态是否处于活动状态。

func application(_ application: UIApplication, didReceiveRemoteNotification userInfo: [AnyHashable : Any], fetchCompletionHandler completionHandler: @escaping (UIBackgroundFetchResult) -> Void) {
    if application.applicationState == .active {
      if let aps = userInfo["aps"] as? NSDictionary {
        if let alertMessage = aps["alert"] as? String {
          let alert = UIAlertController(title: "Notification", message: alertMessage, preferredStyle: UIAlertControllerStyle.alert)
          let action = UIAlertAction(title: "Ok", style: .default, handler: nil)
          alert.addAction(action)
          self.window?.rootViewController?.present(alert, animated: true, completion: nil)
        }
      }
    }
    completionHandler(.newData)
  }

From this if a user need message then he can get alert message.

如果用户需要消息，那么他可以获得警报消息。

回答by Joshpy

I use APNs Provider and json payload as below

我使用 APNs Provider 和 json 负载如下

{
  "aps" : {
    "alert" : {
      "title" : "I am title",
      "body" : "message body."
    },
  "sound" : "default",
  "badge" : 1
  }
}

Due to the provider originates it as a JSON-defined dictionary that iOS converts to an NSDictionaryobject, without subscript like Dictionary, but can use value(forKey:)

由于提供者将其作为 JSON 定义的字典起源，iOS 将其转换为NSDictionary对象，没有像 那样的下标Dictionary，但可以使用value(forKey:)

Reference from here

从这里参考

This's my way for Swift 4

这是我使用 Swift 4 的方式

func application(_ application: UIApplication, didReceiveRemoteNotification userInfo: [AnyHashable : Any], fetchCompletionHandler completionHandler: @escaping (UIBackgroundFetchResult) -> Void) {
    guard application.applicationState == .active else { return }
    guard let alertDict = ((userInfo["aps"] as? NSDictionary)?.value(forKey: "alert")) as? NSDictionary,
        let title = alertDict["title"] as? String,
        let body = alertDict["body"] as? String
        else { return }
    let alertController = UIAlertController(title: title, message: body, preferredStyle: .alert)
    let okAct = UIAlertAction(title: "Ok", style: .default, handler: nil)
    alertController.addAction(okAct)
    self.window?.rootViewController?.present(alertController, animated: true, completion: nil)
    completionHandler(UIBackgroundFetchResult.noData)
}

回答by Erik Peruzzi

This is my version for objC

这是我的 objC 版本

if (userInfo[@"aps"]){
    NSDictionary *aps = userInfo[@"aps"];
    if (aps[@"alert"]){
        NSObject *alert = aps[@"alert"];
        if ([alert isKindOfClass:[NSDictionary class]]){
            NSDictionary *alertDict = aps[@"alert"];
            if (alertDict[@"message"]){
                NSString *message = alertDict[@"message"];
            }
        }
        else if (aps[@"alert"]){
            NSString *alert = aps[@"alert"];
        }
    }
}