iOS 上的电话号码格式

Phone number formatting on iOS

提问by Moni Viki

I have a text field where the user enters data. It's a phone number field. If the user enters 1234567890, I want it displayed as (123)-(456)-7890as the user types. How is this possible?

我有一个用户输入数据的文本字段。这是一个电话号码字段。如果用户输入1234567890，我希望它显示为(123)-(456)-7890用户键入。这怎么可能？

回答by wan

This will help you

这会帮助你

Format (xxx) xxx-xxxx

格式（xxx）xxx-xxxx

- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string
{
    int length = (int)[self getLength:textField.text];
    //NSLog(@"Length  =  %d ",length);

    if(length == 10)
    {
        if(range.length == 0)
            return NO;
    }

    if(length == 3)
    {
        NSString *num = [self formatNumber:textField.text];
        textField.text = [NSString stringWithFormat:@"(%@) ",num];

        if(range.length > 0)
            textField.text = [NSString stringWithFormat:@"%@",[num substringToIndex:3]];
    }
    else if(length == 6)
    {
        NSString *num = [self formatNumber:textField.text];
        //NSLog(@"%@",[num  substringToIndex:3]);
        //NSLog(@"%@",[num substringFromIndex:3]);
        textField.text = [NSString stringWithFormat:@"(%@) %@-",[num  substringToIndex:3],[num substringFromIndex:3]];

        if(range.length > 0)
            textField.text = [NSString stringWithFormat:@"(%@) %@",[num substringToIndex:3],[num substringFromIndex:3]];
    }

    return YES;
}

- (NSString *)formatNumber:(NSString *)mobileNumber
{
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"(" withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@")" withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@" " withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"-" withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"+" withString:@""];

    NSLog(@"%@", mobileNumber);

    int length = (int)[mobileNumber length];
    if(length > 10)
    {
        mobileNumber = [mobileNumber substringFromIndex: length-10];
        NSLog(@"%@", mobileNumber);

    }

    return mobileNumber;
}

- (int)getLength:(NSString *)mobileNumber
{
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"(" withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@")" withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@" " withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"-" withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"+" withString:@""];

    int length = (int)[mobileNumber length];

    return length;
}

回答by bryguy1300

This felt more clear and handles removing any unwanted characters much more nicely. Formats correctly for 1?(###)?###?####or (###)?###?####

这感觉更清晰，并且可以更好地处理删除任何不需要的字符。格式正确为1?(###)?###?####或(###)?###?####

- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string
{
    NSString *newString = [textField.text stringByReplacingCharactersInRange:range withString:string];
    NSArray *components = [newString componentsSeparatedByCharactersInSet:[[NSCharacterSet decimalDigitCharacterSet] invertedSet]];
    NSString *decimalString = [components componentsJoinedByString:@""];

    NSUInteger length = decimalString.length;
    BOOL hasLeadingOne = length > 0 && [decimalString characterAtIndex:0] == '1';

    if (length == 0 || (length > 10 && !hasLeadingOne) || (length > 11)) {
        textField.text = decimalString;
        return NO;
    }

    NSUInteger index = 0;
    NSMutableString *formattedString = [NSMutableString string];

    if (hasLeadingOne) {
        [formattedString appendString:@"1 "];
        index += 1;
    }

    if (length - index > 3) {
        NSString *areaCode = [decimalString substringWithRange:NSMakeRange(index, 3)];
        [formattedString appendFormat:@"(%@) ",areaCode];
        index += 3;
    }

    if (length - index > 3) {
        NSString *prefix = [decimalString substringWithRange:NSMakeRange(index, 3)];
        [formattedString appendFormat:@"%@-",prefix];
        index += 3;
    }

    NSString *remainder = [decimalString substringFromIndex:index];
    [formattedString appendString:remainder];

    textField.text = formattedString;

    return NO;
}

回答by datinc

The code bellow is what I typically use. The format is different but you get the picture. This will handle input such as '123df#$@$gdfg45-+678dfg901' and output '1 [phone]'

下面的代码是我通常使用的。格式不同，但你得到了图片。这将处理诸如 '123df#$@$gdfg45-+678dfg901' 和输出 '1 [phone]' 之类的输入

#import "NSString+phoneNumber.h"

@implementation NSString (phoneNumber)

-(NSString*) phoneNumber{
    static NSCharacterSet* set = nil;
    if (set == nil){
        set = [[NSCharacterSet decimalDigitCharacterSet] invertedSet];
    }
    NSString* phoneString = [[self componentsSeparatedByCharactersInSet:set] componentsJoinedByString:@""];
    switch (phoneString.length) {
        case 7: return [NSString stringWithFormat:@"%@-%@", [phoneString substringToIndex:3], [phoneString substringFromIndex:3]];
        case 10: return [NSString stringWithFormat:@"(%@) %@-%@", [phoneString substringToIndex:3], [phoneString substringWithRange:NSMakeRange(3, 3)],[phoneString substringFromIndex:6]];
        case 11: return [NSString stringWithFormat:@"%@ (%@) %@-%@", [phoneString substringToIndex:1], [phoneString substringWithRange:NSMakeRange(1, 3)], [phoneString substringWithRange:NSMakeRange(4, 3)], [phoneString substringFromIndex:7]];
        case 12: return [NSString stringWithFormat:@"+%@ (%@) %@-%@", [phoneString substringToIndex:2], [phoneString substringWithRange:NSMakeRange(2, 3)], [phoneString substringWithRange:NSMakeRange(5, 3)], [phoneString substringFromIndex:8]];
        default: return nil;
    }
}

@end

回答by Michael Enriquez

We wrote a custom NSFormatter subclass for phone numbers here: https://github.com/edgecase/PhoneNumberFormatter

我们在这里为电话号码编写了一个自定义的 NSFormatter 子类：https: //github.com/edgecase/PhoneNumberFormatter

You can use it like any other NSFormatter subclass.

您可以像使用任何其他 NSFormatter 子类一样使用它。

回答by Yangel

Thanks so much for the first answer but, i think, that method -(int)getLength:(NSString*)mobileNumberis useless. You can try something like below:

非常感谢您的第一个答案，但我认为该方法-(int)getLength:(NSString*)mobileNumber没用。您可以尝试以下操作：

- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string{

int length = [[self formatNumber:[textField text]] length];

if (length == 10) {
    if(range.length == 0) {
        return NO;
    }
}

if (length == 3) {
    NSString *num = [self formatNumber:[textField text]];
    textField.text = [NSString stringWithFormat:@"(%@) ",num];
    if (range.length > 0) {
        [textField setText:[NSString stringWithFormat:@"%@",[num substringToIndex:3]]];
    }
}
else if (length == 6) {
    NSString *num = [self formatNumber:[textField text]];
    [textField setText:[NSString stringWithFormat:@"(%@) %@-",[num  substringToIndex:3],[num substringFromIndex:3]]];
    if (range.length > 0) {
        [textField setText:[NSString stringWithFormat:@"(%@) %@",[num substringToIndex:3],[num substringFromIndex:3]]];
    }
}

return YES;
}

- (NSString*)formatNumber:(NSString*)mobileNumber {
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"(" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@")" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@" " withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"-" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"+" withString:@""];

int length = [mobileNumber length];

if (length > 10) {
    mobileNumber = [mobileNumber substringFromIndex: length-10];
}

return mobileNumber;
}

回答by ekscrypto

For those of you who require international number formatting: https://code.google.com/p/libphonenumber/

对于那些需要国际号码格式的人：https: //code.google.com/p/libphonenumber/

Comes with C++, Java and JavaScript implementations. Should be easy to wrap the C++ implementations in a .mm file and write a small Objective-C wrapper around it.

附带 C++、Java 和 JavaScript 实现。将 C++ 实现包装在 .mm 文件中并在其周围编写一个小的 Objective-C 包装器应该很容易。

回答by Kappe

A valid option is https://github.com/iziz/libPhoneNumber-iOSAll the other answer cover only a small part of the possibilities and combinations, this library actually parse and validate EVERY phone number, and identify:

一个有效的选项是https://github.com/iziz/libPhoneNumber-iOS所有其他答案只涵盖了可能性和组合的一小部分，这个库实际上解析和验证每个电话号码，并识别：

• Nationality
• phone number type
• National carrier

• 国籍
• 电话号码类型
• 国家承运人

回答by rizk.taker

Relevant for U.S. Phone Numbers:

与美国电话号码相关：

Adding to @wan's post, I added a conditional statement if the user starts with the country code (1). That way, it will format to be: 1 (XXX) XXX-XXXX instead of (1XX) XXX-XXXX.

添加到@wan 的帖子中，如果用户以国家/地区代码 (1) 开头，我添加了一个条件语句。这样，它将格式为：1 (XXX) XXX-XXXX 而不是 (1XX) XXX-XXXX。

    - (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string{
    textField = self.phoneNumberTextField;

    NSInteger length = [self getLength:textField.text];
    //NSLog(@"Length  =  %d ",length);

    if ([textField.text hasPrefix:@"1"]) {
        if(length == 11)
        {
            if(range.length == 0)
                return NO;
        }
        if(length == 4)
        {
            NSString *num = [self formatNumber:textField.text];
            textField.text = [NSString stringWithFormat:@"%@ (%@) ",[num substringToIndex:1],[num substringFromIndex:1]];
            if(range.length > 0)
                textField.text = [NSString stringWithFormat:@"%@",[num substringToIndex:4]];
        }
        else if(length == 7)
        {
            NSString *num = [self formatNumber:textField.text];
            NSRange numRange = NSMakeRange(1, 3);
            textField.text = [NSString stringWithFormat:@"%@ (%@) %@-",[num substringToIndex:1] ,[num substringWithRange:numRange],[num substringFromIndex:4]];
            if(range.length > 0)
                textField.text = [NSString stringWithFormat:@"(%@) %@",[num substringToIndex:3],[num substringFromIndex:3]];
        }

    } else {
        if(length == 10)
        {
            if(range.length == 0)
                return NO;
        }

        if(length == 3)
        {
            NSString *num = [self formatNumber:textField.text];
            textField.text = [NSString stringWithFormat:@"(%@) ",num];
            if(range.length > 0)
                textField.text = [NSString stringWithFormat:@"%@",[num substringToIndex:3]];
        }
        else if(length == 6)
        {
            NSString *num = [self formatNumber:textField.text];

            textField.text = [NSString stringWithFormat:@"(%@) %@-",[num  substringToIndex:3],[num substringFromIndex:3]];
            if(range.length > 0)
                textField.text = [NSString stringWithFormat:@"(%@) %@",[num substringToIndex:3],[num substringFromIndex:3]];
        }
    }
    return YES;
}

-(NSString*)formatNumber:(NSString*)mobileNumber
{
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"(" withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@")" withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@" " withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"-" withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"+" withString:@""];

    NSLog(@"%@", mobileNumber);

    NSInteger length = [mobileNumber length];
    if(length > 10)
    {
        mobileNumber = [mobileNumber substringFromIndex: length-10];
        NSLog(@"%@", mobileNumber);

    }


    return mobileNumber;
}
-(NSInteger)getLength:(NSString*)mobileNumber
{

    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"(" withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@")" withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@" " withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"-" withString:@""];
    mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"+" withString:@""];

    NSInteger length = [mobileNumber length];

    return length;        
}

回答by yunhasnawa

Maybe you could use this simple method:

也许你可以使用这个简单的方法：

+ (NSString*) formatPhoneNumber:(NSString *)phoneNumber codeLength:(int) code segmentLength:(int) segment
{
    NSString* result = @"";

    int length = [phoneNumber length];

    NSString* firstSegment = @"";
    NSString* restSegment = @"";

    for (int i=0; i<length; i++) {

        char c = [phoneNumber characterAtIndex:i];

        if(i < code)
            firstSegment = [firstSegment stringByAppendingFormat:@"%c", c];
        else
        {
            restSegment = [restSegment stringByAppendingFormat:@"%c", c];

            int threshold = (i - code) + 1;

            if((threshold % segment == 0) && (threshold > 0) && !(threshold > length))
                restSegment = [restSegment stringByAppendingFormat:@"%c", '-'];
        }

    }

    result = [result stringByAppendingFormat:@"%@-%@", firstSegment, restSegment];

    return result;
}

Assuming above method is in Contactclass, just use the method like this:

假设上面的方法是在Contact类中，只需使用这样的方法：

NSString* phoneNumber = @"085755023455";

NSString* formattedNumber = [Contact formatPhoneNumber:phoneNumber codeLength:3 segmentLength:4];

That would be resulting something like:

这将导致类似：

085-7550-2345-5

回答by Dharmbir Singh

SWIFT

迅速

func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {        
            let length = self.getTextLength(textField.text)



            if length == 10{
                if range.length == 0{
                    return false
                }
            }

            if length == 3{

                var num : String = self.formatNumber(textField.text)

                textField.text = num + "-"
                if(range.length > 0){
                    textField.text = (num as NSString).substringToIndex(3)
                }
            }
            else if length == 6{

                var num : String = self.formatNumber(textField.text)

                let prefix  = (num as NSString).substringToIndex(3)
                let postfix = (num as NSString).substringFromIndex(3)

                textField.text = prefix + "-" + postfix + "-"

                if range.length > 0{
                    textField.text = prefix + postfix
                }
            }

            return true
    }




func getTextLength(mobileNo: String) -> NSInteger{

        var str : NSString = mobileNo as NSString
        str = str.stringByReplacingOccurrencesOfString("(", withString: "")
        str = str.stringByReplacingOccurrencesOfString(")", withString: "")
        str = str.stringByReplacingOccurrencesOfString(" ", withString: "")
        str = str.stringByReplacingOccurrencesOfString("-", withString: "")
        str = str.stringByReplacingOccurrencesOfString("+", withString: "")

        return str.length
    }

    func formatNumber(mobileNo: String) -> String{
        var str : NSString = mobileNo as NSString
        str = str.stringByReplacingOccurrencesOfString("(", withString: "")
        str = str.stringByReplacingOccurrencesOfString(")", withString: "")
        str = str.stringByReplacingOccurrencesOfString(" ", withString: "")
        str = str.stringByReplacingOccurrencesOfString("-", withString: "")
        str = str.stringByReplacingOccurrencesOfString("+", withString: "")

        if str.length > 10{
            str = str.substringFromIndex(str.length - 10)
        }

        return str as String
    }