java.net.URLEncoder.encode 将空格编码为 + 但我需要 %20
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java.net.URLEncoder.encode encodes space as + but I need %20
提问by Cote Mounyo
As the title says: which encoder would give me space as %20as opposed to +? I need it for android. java.net.URLEncoder.encode gives +
正如标题所说：哪个编码器会给我空间%20而不是+？我需要它用于安卓。java.net.URLEncoder.encode 给出+
回答by zennon
You have to replace the +by yourself.
必须自己更换 +。
Example:
例子：
System.out.println(java.net.URLEncoder.encode("Hello World", "UTF-8").replace("+", "%20"));
For more look at this post:
更多信息请看这篇文章：
回答by zapl
Android has it's own Uriclass which you could use.
Android 有它自己的Uri类，您可以使用它。
E.g.
例如
String url = Uri.parse("http://www.google.com").buildUpon()
.appendQueryParameter("q", "foo bar")
.appendQueryParameter("xml", "<Hell?>")
.build().toString();
results in
结果是
http://www.google.com?q=foo%20bar&xml=%3CHell%C3%B6%3E
http://www.google.com?q=foo%20bar&xml=%3CHell%C3%B6%3E
UriEncodes characters in the given string as '%'-escaped octets using the UTF-8 scheme. Leaves letters ("A-Z", "a-z"), numbers ("0-9"), and unreserved characters ("_-!.~'()*") intact.
Uri使用 UTF-8 方案将给定字符串中的字符编码为 '%' 转义八位字节。保持字母（“AZ”、“az”）、数字（“0-9”）和非保留字符（“_-!.~'()*”）不变。
Note: only _-.*are considered unreserved characters by URLEncoder. !~'()would get converted to %21%7E%27%28%29.
注意：仅_-.*被 视为非保留字符URLEncoder。!~'()将被转换为%21%7E%27%28%29.
