在 PHP 中，有没有一种简单的方法来获取一个月的第一个和最后一个日期？
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In PHP, is there an easy way to get the first and last date of a month?
提问by Thomas Owens
I need to get the first and last day of a month in the format YYYY-MM-DD given only the month and year. Is there a good, easy way to do this?
我需要以 YYYY-MM-DD 格式获取一个月的第一天和最后一天，仅给出月份和年份。有没有好的，简单的方法来做到这一点？
回答by Micha? Rudnicki
回答by Biri
First day is always YYYY-MM-01, isn't it? Example: date("Y-M-d", mktime(0, 0, 0, 8, 1, 2008))
第一天总是YYYY-MM-01，不是吗？例子：date("Y-M-d", mktime(0, 0, 0, 8, 1, 2008))
Last day is the previous day of the next month's first day:
最后一天是下个月第一天的前一天：
$date = new DateTime("2008-09-01");
$date->modify("-1 day");
echo $date->format("Y-m-d");
回答by Niyaz
The first day of the month is always 1. So it will become
这个月的第一天总是 1。所以它会变成
YYYY-MM-01
the last day can be calculated as:
最后一天可以计算为：
<?php
$num = cal_days_in_month(CAL_GREGORIAN, 8, 2003); // 31
echo "There was $num days in August 2003";
?>
回答by ZombieSheep
OK, first is dead easy.
好的，首先很容易。
date ('Y-m-d', mktime(0,0,0,MM,01,YYYY));
Last is a little trickier, but not much.
最后一个有点棘手，但不是很多。
date ('Y-m-d', mktime(0,0,0,MM + 1,-1,YYYY));
If I remember my PHP date stuff correctly...
如果我正确记住了我的 PHP 日期内容...
**edit - Gah! Beaten to it about a million times...
**编辑 - 啊！被它打了大约一百万次......
Edit by Pat:
帕特编辑：
Last day should have been
最后一天应该是
date ('Y-m-d', mktime(0,0,0,$MM + 1,0,$YYYY)); // Day zero instead of -1
回答by Eranda
<?php
echo "Month Start - " . $monthStart = date("Y-m-1") . "<br/>";
$num = cal_days_in_month(CAL_GREGORIAN, date("m"), date("Y"));
echo "Monthe End - " . $monthEnd = date("Y-m-".$num);
?>
回答by Eranda
The easiest way to do this with PHP is
使用 PHP 执行此操作的最简单方法是
$dateBegin = strtotime("first day of last month");
$dateEnd = strtotime("last day of last month");
echo date("MYDATEFORMAT", $dateBegin);
echo "<br>";
echo date("MYDATEFORMAT", $dateEnd);
Or the last week
或者上周
if (date('N', time()) == 7) {
$dateBegin = strtotime("-2 weeks Monday");
$dateEnd = strtotime("last Sunday");
} else {
$dateBegin = strtotime("Monday last week");
$dateEnd = strtotime("Sunday last week");
}
Or the last year
或者去年
$dateBegin = strtotime("1/1 last year");
$dateEnd = strtotime("12/31 this year");
回答by Nate
try this to get the number of days in the month:
试试这个来获得当月的天数：
$numdays = date('t', mktime(0, 0, 0, $m, 1, $Y));
回答by csonuryilmaz
Example; I want to get first day and last day of current month.
例子; 我想获得当月的第一天和最后一天。
$month = (int) date('F');
$year = (int) date('Y');
date('Y-m-d', mktime(0, 0, 0, $month + 1, 1, $year)); //first
date('Y-m-d', mktime(0, 0, 0, $month + 2, 0, $year)); //last
When you run this for instance at date 2015-01-09, the first and last values will be sequentially;
例如，当您在 2015-01-09 日期运行它时，第一个和最后一个值将按顺序排列；
2015-01-01
2015-01-31
Tested.
测试。
回答by arturwwl
From here(get next month last day)that is marked as duplicated, so i can't add comment there, but people can got bad answers from there.
从这里（最后一天获取下个月）标记为重复，所以我无法在那里添加评论，但人们可以从那里得到错误的答案。
Correct one for last day of next month:
更正下个月最后一天的一个：
echo ((new DateTime(date('Y-m').'-01'))->modify('+1 month')->format('Y-m-t'));
Correct one for first day of next month:
更正下个月第一天的一个：
echo ((new DateTime(date('Y-m').'-01'))->modify('+1 month')->format('Y-m-01'));
Code like this will be providing March from January, so that's not what could be expected.
像这样的代码将从一月开始提供三月，所以这不是预期的。
echo ((new DateTime())->modify('+1 month')->format('Y-m-t'));
echo ((new DateTime())->modify('+1 month')->format('Y-m-t'));
回答by Pat
By the way @ZombieSheep solution
顺便说一下@ZombieSheep 解决方案
date ('Y-m-d', mktime(0,0,0,$MM + 1,-1,$YYYY));
does not work it should be
不工作它应该是
date ('Y-m-d', mktime(0,0,0,$MM + 1,0,$YYYY)); // Day zero instead of -1
Of course @Micha? S?aby's accepted solution is the simplest.
当然@Micha？S?aby 接受的解决方案是最简单的。
