Python 检查对象是数字还是布尔值
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Check if object is a number or boolean
提问by Joakim
Design a logical expression equivalent to the following statement:
xis a list of three or five elements, the second element of which is the string'Hip'and the first of which is not a number or Boolean.
设计一个与以下语句等效的逻辑表达式：
x是一个包含三个或五个元素的列表，其中第二个元素是字符串'Hip'，第一个元素不是数字或布尔值。
What I have:
我拥有的：
x = ['Head', 'Hip', 10]
print x[1] is 'Hip'
My question: How do you check for whether or not it is a Boolean or a number?
我的问题：你如何检查它是布尔值还是数字？
采纳答案by Lev Levitsky
To answer the specific question:
要回答具体问题：
isinstance(x[0], (int, float))
This checks if x[0]is an instance of any of the types in the tuple (int, float).
这将检查是否x[0]是元组中任何类型的实例(int, float)。
You can add boolin there, too, but it's not necessary, because boolis itself a subclass of int.
您也可以bool在那里添加，但这不是必需的，因为bool它本身就是int.
Doc reference:
文档参考：
To comment on your current code, you shouldn't rely on interning of short strings. You are supposed to compare strings with the ==operator:
要评论您当前的代码，您不应该依赖于短字符串的实习。您应该将字符串与==运算符进行比较：
x[1] == 'Hip'
回答by Peyman Karimi
import types
type(x) == types.BooleanType
回答by CurlyMo
Easiest i would say:
最简单的我会说：
type(x) == type(True)
回答by Thijs Cobben
回答by Justin Golden
You should compare the type of xto the boolclass:
您应该将 的类型x与bool类进行比较：
type(x) == bool
or:
或者：
type(x) == type(True)
Here is more on the type method
这里有更多关于类型方法的信息
From Data model docs:
来自数据模型文档：
Booleans (bool)
These represent the truth values False and True. The two objects representing the values False and True are the only Boolean objects. The Boolean type is a subtype of the integer type, and Boolean values behave like the values 0 and 1, respectively, in almost all contexts, the exception being that when converted to a string, the strings "False" or "True" are returned, respectively.
布尔值 (bool)
这些代表真值 False 和 True。表示值 False 和 True 的两个对象是唯一的布尔对象。布尔类型是整数类型的子类型，布尔值的行为分别类似于值 0 和 1，几乎在所有上下文中，例外是转换为字符串时，返回字符串“False”或“True” ， 分别。
回答by Michael
I follow the recent answer who tell to use typeand it seems to be the incorrect way according to pylintvalidation:
我遵循了最近的答案 who tell to use type，根据pylint验证，这似乎是不正确的方法：
I got the message:
我收到消息：
C0123: Using type() instead of isinstance() for a typecheck. (unidiomatic-typecheck)
C0123：使用 type() 而不是 isinstance() 进行类型检查。（单语类型检查）
Even if it's an old answer, the correct one is the accepted answer of @Lev Levitsky:
即使这是一个旧答案，正确的答案是@Lev Levitsky 已接受的答案：
isinstance(x[0], (int, float))
