java 在jsp中使用spring:eval显示属性值
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Using spring:eval display property value in jsp
提问by sats
I am looking for help to display the Spring property value in a jsp file.
我正在寻找帮助以在 jsp 文件中显示 Spring 属性值。
I found one link which is having the same requirement of mine. Click Using spring:eval inside hasRole
我找到了一个与我有相同要求的链接。单击在 hasRole 中使用 spring:eval
I am using Spring 2.5
我正在使用Spring 2.5
This is my applicationContext-util.xml file:
这是我的 applicationContext-util.xml 文件：
xmlns:util="http://www.springframework.org/schema/util"
xmlns:context="http://www.springframework.org/schema/context"
http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util-2.5.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-2.5.xsd
<util:properties id="viewPropertyConfigurer" location="classpath:conf/app_config.properties"/>
<context:property-placeholder properties-ref="viewPropertyConfigurer" />
in my menu.jsp
在我的 menu.jsp 中
<%@ taglib prefix="spring" uri="http://www.springframework.org/tags" %>
<spring:eval expression="@viewPropertyConfigurer.getProperty('role.admin')" />
in lib folder I also have spring-web-2.5.6.jar file to make sure the eval should work fine in jsp. But not sure what is the issue once i add spring:eval tag the jsp is not at all loading it throws
在 lib 文件夹中，我还有 spring-web-2.5.6.jar 文件以确保 eval 在 jsp 中正常工作。但是不确定一旦我添加了 spring:eval 标签，jsp 就根本没有加载它抛出的问题
[ERROR,context.JspTilesRequestContext,http-8080-1] -[UID=galips - SessionID=691A896E807850568DF9B0F5356F6CB2] - JSPException while including path '/WEB-INF/jsp/menu.jsp'.
In my application I am using servlet filter as well hope it will not be an issue.
在我的应用程序中，我也使用 servlet 过滤器，希望它不会成为问题。
Thanks for your help in advance.
提前感谢您的帮助。
采纳答案by Pavel Horal
As far as I know EvalTagwas added in Spring 3 (@since 3.0.1). If you are using Spring 2.5, then you don't have <spring:eval>support.
据我所知EvalTag是在 Spring 3 ( @since 3.0.1) 中添加的。如果您使用的是 Spring 2.5，那么您就没有<spring:eval>支持。
Possible solutions:
可能的解决方案：
- switch to Spring 3+
- use a custom handler interceptor to add additional information to your request
- write your own tag to pull up information from application context
- 切换到 Spring 3+
- 使用自定义处理程序拦截器向您的请求添加其他信息
- 编写您自己的标签以从应用程序上下文中提取信息
Update (option 2 example):
更新（选项 2 示例）：
public class CommonViewAttributesInterceptor extends HandlerInterceptorAdapter {
private static final String PROPERTIES_ATTR = "properties";
private Properties properties = new Properties();
@Override
public void postHandle(HttpServletRequest request, HttpServletResponse response,
Object handler, ModelAndView modelAndView) throws Exception {
request.setAttribute(PROPERTIES_ATTR, properties);
}
public void setPropertiesSource(Resource resource) throws IOException {
InputStream input = resource.getInputStream();
try {
properties.load(input);
} finally {
input.close();
}
}
}
Then you need to configure this interceptor within your handler mapping.
然后你需要在你的处理程序映射中配置这个拦截器。
