C++ - 获取特定内存地址的值
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C++ - Get value of a particular memory address
提问by Zyyk Savvins
I was wondering whether it is possible to do something like this:
我想知道是否有可能做这样的事情:
unsigned int address = 0x0001FBDC; // Random address :P
int value = *address; // Dereference of address
Meaning, is it possible to get the value of a particular address in memory ?
意思是,是否有可能获得内存中特定地址的值?
Thanks
谢谢
回答by Kerrek SB
You can and should write it like this:
你可以而且应该这样写:
#include <cstdint>
uintptr_t p = 0x0001FBDC;
int value = *reinterpret_cast<int *>(p);
Note that unless there is some guarantee that p
points to an integer, this is undefined behaviour. A standard operating system will kill your process if you try to access an address that it didn't expect you to address. However, this may be a common pattern in free-standing programs.
请注意,除非有一些保证p
指向整数,否则这是未定义的行为。如果您尝试访问它不希望您访问的地址,标准操作系统将终止您的进程。但是,这可能是独立程序中的常见模式。
(Earlier versions of C++ should say #include <stdint.h>
and intptr_t
.)
(早期版本的 C++ 应该说#include <stdint.h>
和intptr_t
。)