使用 PHP 将分钟数转换为小时和分钟
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Convert number of minutes into hours & minutes using PHP
提问by Rob
I have a variable called $final_time_savingwhich is just a number of minutes, 250 for example.
我有一个名为的变量$final_time_saving，它只是几分钟，例如 250。
How can I convert that number of minutes into hours and minutes using PHP in this format:
如何使用 PHP 以这种格式将分钟数转换为小时数和分钟数：
4 hours 10 minutes
4 hours 10 minutes
回答by Martin Bean
<?php
function convertToHoursMins($time, $format = '%02d:%02d') {
if ($time < 1) {
return;
}
$hours = floor($time / 60);
$minutes = ($time % 60);
return sprintf($format, $hours, $minutes);
}
echo convertToHoursMins(250, '%02d hours %02d minutes'); // should output 4 hours 17 minutes
回答by Alastair
echo date('H:i', mktime(0,257));
回答by Sjoerd
$hours = floor($final_time_saving / 60);
$minutes = $final_time_saving % 60;
回答by Glavi?
You can achieve this with DateTimeextension, which will also work for number of minutes that is larger than one day (>= 1440):
您可以通过DateTime扩展来实现这一点，它也适用于大于一天 ( >= 1440)的分钟数：
$minutes = 250;
$zero = new DateTime('@0');
$offset = new DateTime('@' . $minutes * 60);
$diff = $zero->diff($offset);
echo $diff->format('%a Days, %h Hours, %i Minutes');
回答by Mihail Velikov
@Martin Bean's answer is perfectly correct but in my point of view it needs some refactoring to fit what a regular user would expect from a website (web system).
I think that when minutes are below 10 a leading zero must be added.
ex: 10:01, not 10:1
@Martin Bean 的回答是完全正确的，但在我看来，它需要进行一些重构以适应普通用户对网站（网络系统）的期望。
我认为当分钟数低于 10 时，必须添加前导零。
例如：10:01，而不是 10:1
I changed code to accept $time = 0since 0:00 is better than 24:00.
我更改了代码以接受，$time = 0因为 0:00 比 24:00 好。
One more thing - there is no case when $timeis bigger than 1439 - which is 23:59 and next value is simply 0:00.
还有一件事 - 没有$time大于 1439 的情况 - 即 23:59，下一个值只是 0:00。
function convertToHoursMins($time, $format = '%d:%s') {
settype($time, 'integer');
if ($time < 0 || $time >= 1440) {
return;
}
$hours = floor($time/60);
$minutes = $time%60;
if ($minutes < 10) {
$minutes = '0' . $minutes;
}
return sprintf($format, $hours, $minutes);
}
回答by Mike
$t = 250;
$h = floor($t/60) ? floor($t/60) .' hours' : '';
$m = $t%60 ? $t%60 .' minutes' : '';
echo $h && $m ? $h.' and '.$m : $h.$m;
4 hours and 10 minutes
4小时10分钟
回答by Lurvik
Sorry for bringing up an old topic, but I used some code from one of these answers a lot, and today I told myself I could do it without stealing someone's code. I was surprised how easy it was. What I wanted is 510 minutes to be return as 08:30, so this is what the code does.
很抱歉提出了一个旧话题，但我经常使用其中一个答案中的一些代码，今天我告诉自己我可以在不窃取某人代码的情况下做到这一点。我很惊讶这是多么容易。我想要的是 510 分钟作为 08:30 返回，所以这就是代码的作用。
function tm($nm, $lZ = true){ //tm = to military (time), lZ = leading zero (if true it returns 510 as 08:30, if false 8:30
$mins = $nm % 60;
if($mins == 0) $mins = "0$mins"; //adds a zero, so it doesn't return 08:0, but 08:00
$hour = floor($nm / 60);
if($lZ){
if($hour < 10) return "0$hour:$mins";
}
return "$hour:$mins";
}
I use short variable names because I'm going to use the function a lot, and I'm lazy.
我使用短变量名是因为我会经常使用这个函数，而且我很懒。
回答by Seif.ben
The easiest way is :
最简单的方法是：
gmdate('H:i', $numberOfSeconds * 60)
回答by kelaskakap
Just in case you want to something like:
以防万一你想要这样的东西：
echo date('G \h\o\u\r\s i \m\i\n\u\t\e\s', mktime(0, 90)); //will return 1 hours 30 minutes
echo date('G \j\a\m i \m\e\n\i\t', mktime(0, 90)); //will return 1 jam 30 menit
回答by HIR
function hour_min($minutes){// Total
if($minutes <= 0) return '00 Hours 00 Minutes';
else
return sprintf("%02d",floor($minutes / 60)).' Hours '.sprintf("%02d",str_pad(($minutes % 60), 2, "0", STR_PAD_LEFT)). " Minutes";
}
echo hour_min(250); //Function Call will return value : 04 Hours 10 Minutes
