typescript 如何将 Observable 转换为 BehaviorSubject?

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时间:2020-10-21 05:43:11  来源:igfitidea点击:

How to convert an Observable into a BehaviorSubject?

javascripttypescriptrxjsobservablebehaviorsubject

提问by awmleer

I'm trying to convert an Observable into a BehaviorSubject. Like this:

我正在尝试将 Observable 转换为 BehaviorSubject。像这样:

a$ = new Observable()
b$ = BehaviorSubject.create(new BehaviorSubject(123), a$)
// 

I have also tried:

我也试过:

a$ = new Observable()
b$ = new BehaviorSubject(a$, 123)
// 

And:

和:

a$ = new Observable()
b$ = a$.asBehaviorSubject(123)
// 

And:

和:

a$ = new Observable()
b$ = a$.pipe(
  toBehaviorSubject(123)
)
// 

But none of these works. For now I have to implement like this:

但这些都不起作用。现在我必须像这样实现:

a$ = new Observable()
b$ = new BehaviorSubject(123)
a$.subscribe(b$)
// 

This would be a little bit ugly in a class:

这在课堂上会有点难看:

class Foo() {
  a$ = new Observable() // Actually, a$ is more complicated than this.
  b$ = new BehaviorSubject(123)

  constructor() {
    this.a$.subscribe(this.b$)
  }
}

So, is there a simpler way to convert a Observable to a BehaviorSubject without using class constructor?

那么,是否有一种更简单的方法可以在不使用类构造函数的情况下将 Observable 转换为 BehaviorSubject?



This is my real case:

这是我的真实案例:

export class Foo {
  autoCompleteItems$ = new BehaviorSubject<string[]>(null)
  autoCompleteSelected$ = new BehaviorSubject<number>(-1)
  autoCompleteSelectedChange$ = new Subject<'up'|'down'>()

  constructor() {
    this.autoCompleteItems$.pipe(
      switchMap((items) => {
        if (!items) return EMPTY
        return this.autoCompleteSelectedChange$.pipe(
          startWith('down'),
          scan<any, number>((acc, value) => {
            if (value === 'up') {
              if (acc <= 0) {
                return items.length - 1
              } else {
                return acc - 1
              }
            } else {
              if (acc >= items.length - 1) {
                return 0
              } else {
                return acc + 1
              }
            }
          }, -1)
        )
      })
    ).subscribe(this.autoCompleteSelected$)
  }

  doAutoComplete = () => {
    const item = this.autoCompleteItems$.value[this.autoCompleteSelected$.value]
    // do something with `item`
  }
}

采纳答案by yaya

No need to convert it. just create a subject and attach observable to it. example:

不需要转换它。只需创建一个主题并将可观察对象附加到它。例子:

var obs = new rxjs.Observable((s) => {setTimeout(()=>{s.next([1])} , 500)}) //observable
var sub = new rxjs.BehaviorSubject([0]) //create subject
obs.subscribe(sub) //attach observable to subject
setTimeout(() => {sub.next([2, 3])}, 1500) //subject updated
sub.subscribe(a => console.log(a)) //subscribe to subject

Note: obs.subscribe(sub)is equivalent to :

注意obs.subscribe(sub)相当于:

obs.subscribe({
  next: v => sub.next(v),
  error: v => sub.error(v),
  complete: () => sub.complete()
})

run it online

在线运行

回答by tmuecksch

This is how I convert my Observables to BehaviorSubjects:

这就是我将 Observables 转换为 BehaviorSubjects 的方式:

import { Observable, BehaviorSubject } from 'rxjs';

export function convertObservableToBehaviorSubject<T>(observable: Observable<T>, initValue: T): BehaviorSubject<T> {
    const subject = new BehaviorSubject(initValue);

    observable.subscribe({
        complete: () => subject.complete(),
        error: x => subject.error(x),
        next: x => subject.next(x)
    });

    return subject;
}

回答by Luillyfe

I have pretty concerns about the use case too. But here it comes a solution, feel free vote down as long you leave feedback too. Since BehaviourSubjectand any other Subjectare Observables,

我也很担心用例。但这里有一个解决方案,只要您也留下反馈,请随意投票。由于BehaviourSubject和任何其他Subject都是Observables

import { BehaviorSubject, from } from 'rxjs'; 
import { map, mergeMap } from 'rxjs/operators';


const source$ = from([1,2,3,4,5,6,7,8,9]);
const bs = new BehaviorSubject('start')
    .pipe(
        mergeMap(() => source$)
    );

bs.subscribe(console.log);