Java 在 Tomcat 上访问 wsdl

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时间:2020-08-13 06:59:59  来源:igfitidea点击:

accessing wsdl on Tomcat

javatomcatwsdlglassfishjax-ws

提问by Krt_Malta

I have a web service and I was deploying it on GlassFish. I accessed its wsdl through http://localhost:10697/APIService/APIServiceService?wsdl.

我有一个 Web 服务,我将它部署在 GlassFish 上。我通过http://localhost:10697/APIService/APIServiceService?wsdl访问了它的wsdl

Now I ported the WAR file to a Tomcat 6.0.24 and it is deployed. However I am trying to access its wsdl using http://localhost:8080/APIService/APIServiceService?wsdlbut I'm getting a 404 error. I tried various combinations but none seem to work.

现在我将 WAR 文件移植到 Tomcat 6.0.24 并部署它。但是,我正在尝试使用http://localhost:8080/APIService/APIServiceService?wsdl访问其wsdl,但出现 404 错误。我尝试了各种组合,但似乎都不起作用。

How can I access the wsdl file plz?

请问如何访问wsdl文件?

Thanks and regards,

感谢致敬,

Update:Here you are: web.xml:

更新:你在这里web.xml::

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
    <session-config>
        <session-timeout>
            30
        </session-timeout>
    </session-config>
    <welcome-file-list>
        <welcome-file>index.jsp</welcome-file>
    </welcome-file-list>
</web-app>

I can't find sun-jaxws.xmlhowever... Thanks a lot! Regards

sun-jaxws.xml但是我找不到...非常感谢!问候

采纳答案by Pascal Thivent

The way to access a WSDL is not really container specific, it's more WS-stack specific. The WS-stack in GlassFish is Metro (Metro = JAX-WS RI + WSIT). Did you install/deploy Metro or JAX-WS RI on Tomcat? See Metro on Tomcat 6.xor Running JAX-WS Samples with Tomcat 6.x(JAX-WS RI might be enough in your case) for the steps.

访问 WSDL 的方式实际上并不是特定于容器的,而是更特定于 WS 堆栈的。GlassFish 中的 WS 堆栈是 Metro(Metro = JAX-WS RI + WSIT)。您是否在 Tomcat 上安装/部署了 Metro 或 JAX-WS RI?有关步骤,请参阅Metro on Tomcat 6.xRunning JAX-WS Samples with Tomcat 6.x(在您的情况下 JAX-WS RI 可能就足够了)。

Update:You need to declare the WSServletin the web.xml(see Deploying Metro endpoint):

更新:您需要WSServletweb.xml(请参阅部署 Metro 端点)中声明:

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
  <listener>
    <listener-class>
    com.sun.xml.ws.transport.http.servlet.WSServletContextListener
    </listener-class>
  </listener>
  <servlet>
    <servlet-name>WebServicePort</servlet-name>
    <servlet-class>
    com.sun.xml.ws.transport.http.servlet.WSServlet
    </servlet-class>
    <load-on-startup>1</load-on-startup>
  </servlet>
  <servlet-mapping>
    <servlet-name>WebServicePort</servlet-name>
    <url-pattern>/services/*</url-pattern>
  </servlet-mapping>
  <session-config>
    <session-timeout>60</session-timeout>
  </session-config>
</web-app>

And then in the sun-jaxws.xml(also packaged in WEB-INF), declare your Service Endpoint Interface (SEI):

然后在sun-jaxws.xml(也打包在 WEB-INF 中)中,声明您的服务端点接口 (SEI):

<?xml version="1.0" encoding="UTF-8"?>
<endpoints xmlns="http://java.sun.com/xml/ns/jax-ws/ri/runtime" version="2.0">
  <endpoint
  name="MyHello"
  implementation="hello.HelloImpl"
  url-pattern="/hello"
  />
</endpoints>

And you access the WSDL at:

您可以在以下位置访问 WSDL:

http://localhost:8080/<mycontext>/services/hello?wsdl
           A               B         C       D
  • A is the host and port of the servlet container.
  • B is the name of the war file.
  • C comes from the url-pattern element in the web.xml file.
  • D comes from the ending stem of the url-pattern attribute in the sun-jaxws.xml file.
  • A 是 servlet 容器的主机和端口。
  • B 是war 文件的名称。
  • C 来自 web.xml 文件中的 url-pattern 元素。
  • D 来自 sun-jaxws.xml 文件中 url-pattern 属性的结尾词干。