Python - 使用列表作为函数参数
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Python - use list as function parameters
提问by Jonathan
How can I use a Python list (e.g. params = ['a',3.4,None]) as parameters to a function, e.g.:
如何使用 Python 列表（例如params = ['a',3.4,None]）作为函数的参数，例如：
def some_func(a_char,a_float,a_something):
# do stuff
采纳答案by Neil Vass
You can do this using the splat operator:
您可以使用 splat 运算符执行此操作：
some_func(*params)
This causes the function to receive each list item as a separate parameter. There's a description here: http://docs.python.org/tutorial/controlflow.html#unpacking-argument-lists
这会导致函数将每个列表项作为单独的参数接收。这里有一个描述：http: //docs.python.org/tutorial/controlflow.html#unpacking-argument-lists
回答by Mark Byers
Use an asterisk:
使用星号：
some_func(*params)
回答by btilly
You want the argument unpackingoperator *.
您需要参数解包运算符 *。
回答by Michael David Watson
This has already been answered perfectly, but since I just came to this page and did not understand immediately I am just going to add a simple but complete example.
这已经得到了完美的回答，但由于我刚刚来到这个页面并没有立即理解我只是要添加一个简单但完整的例子。
def some_func(a_char, a_float, a_something):
print a_char
params = ['a', 3.4, None]
some_func(*params)
>> a
