Python 将数组附加到数组
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Python appending array to an array
提问by shubhamj
I am currently working on DES implementation.In one part of the code I have to append array to an array.Below is my code:
我目前正在研究 DES 实现。在代码的一部分中，我必须将数组附加到数组中。下面是我的代码：
C0=[1, 1, 1, 1, 0, 0, 0, 0, 1, 1, 0, 0, 1, 1, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 1, 1, 1]
def Fiestel():
C=[]
C.append(C0)
temp=[0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 1, 0, 0, 1, 1, 0, 0, 1, 1, 1, 1, 0, 0, 0, 1, 1, 1, 1]
C.append(temp)
print(C)
Fiestel()
How do I append an array to an existing array.I even tried declaring C as 2d array.Thankx in advance for helping.
如何将数组附加到现有数组。我什至尝试将 C 声明为 2d 数组。提前感谢您的帮助。
Each element is an array itself.
每个元素本身就是一个数组。
回答by stackoverflowuser2010
You can append the elements of one list to another with the "+" operator.
您可以使用“+”运算符将一个列表的元素附加到另一个列表中。
a = [1, 2, 3]
b = [10, 20]
a = a + b
print a
# [1, 2, 3, 10, 20]
If you want to append the lists and keep them as lists, then try:
如果要附加列表并将它们保留为列表，请尝试：
result = []
result.append(a)
result.append(b)
print result
# [[1, 2, 3], [10, 20]]
回答by Issac Saji
C0=[1, 1, 1, 1, 0, 0, 0, 0, 1, 1, 0, 0, 1, 1, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 1, 1, 1]
def Fiestel():
C=C.append(C0)
temp=[0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 1, 0, 0, 1, 1, 0, 0, 1, 1, 1, 1, 0, 0, 0, 1, 1, 1, 1]
C0=C0.append(temp)
return C
C0=Fiestel()
print (C0)
Try this, I think this is what you are looking for.
试试这个，我想这就是你要找的。
