Python 使用 Django 模板过滤器限制字符数
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Limit number of characters with Django Template filter
提问by Shane Reustle
I am trying to output the first 255 characters of a description on a list of items and am looking for a method to get that.
我正在尝试在项目列表中输出描述的前 255 个字符，并且正在寻找一种方法来获取它。
Example: I have a variable that contains 300 or so characters.
示例：我有一个包含 300 个左右字符的变量。
I call that variable like this, {{ my_variable|characterlimit:255 }}
我这样称呼那个变量， {{ my_variable|characterlimit:255 }}
and it would return only the first 255 characters of that variable.
它只会返回该变量的前 255 个字符。
If this tag doesn't exist, I will simply create it (and suggest that it goes into django), but I wanted to make sure it didn't before I took the time to do that. Thanks!
如果这个标签不存在，我将简单地创建它（并建议它进入 django），但我想在我花时间这样做之前确保它不存在。谢谢！
采纳答案by heckj
If the "my_variable" is a string, you can take advantage of the slice filter, which treats the string as a list of characters. If it's a set of words, the rough equivilant is truncatewords- but that doesn't quite sound like your need.
如果“my_variable”是字符串，您可以利用切片过滤器，它将字符串视为字符列表。如果是一组单词，粗略的等价词是截词- 但这听起来不太像您的需要。
truncatewordsalso adds an ellipsis ...at the end of the truncated result.
truncatewords还在...截断结果的末尾添加省略号。
Usage would be something like
用法类似于
{{ my_variable|slice:":255" }}
回答by Tomek Kopczuk
回答by Felipe Fran?a
If do you want to truncate by word, take a look at this https://docs.djangoproject.com/en/1.4/ref/templates/builtins/#truncatechars
如果你想按字截断，看看这个 https://docs.djangoproject.com/en/1.4/ref/templates/builtins/#truncatechars
回答by Paul Fennema
A more simple way by using the standard template tag is:
使用标准模板标签的更简单方法是：
{{ variable|stringformat:".10s" }}
In this case the 10 is the position argument and for a string it is the maximum number of characters to be displayed.
在这种情况下，10 是位置参数，对于字符串，它是要显示的最大字符数。
回答by northben
回答by Vincent
Using a templatefilter for truncating your text isn't really suitable for a responsive design. Therefore you could also use css to truncate your text that is responsive. I know the OP asked to do this with a django templatefilter.
使用模板过滤器截断文本并不适合响应式设计。因此，您还可以使用 css 截断响应式文本。我知道 OP 要求使用 django 模板过滤器执行此操作。
You can achieve a responsive truncated text using this:
您可以使用以下方法实现响应式截断文本：
.class {
width: 100%;
white-space: nowrap;
overflow: hidden;
text-overflow: ellipsis;
}
