php 为什么PHP json_encode 函数会将UTF-8 字符串转换为十六进制实体?
声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow
原文地址: http://stackoverflow.com/questions/16498286/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Why does the PHP json_encode function convert UTF-8 strings to hexadecimal entities?
提问by David Jones
I have a PHP script that deals with a wide variety of languages. Unfortunately, whenever I try to use json_encode
, any Unicode output is converted to hexadecimal entities. Is this the expected behavior? Is there any way to convert the output to UTF-8 characters?
我有一个处理多种语言的 PHP 脚本。不幸的是,每当我尝试使用 时json_encode
,任何 Unicode 输出都会转换为十六进制实体。这是预期的行为吗?有没有办法将输出转换为 UTF-8 字符?
Here's an example of what I'm seeing:
这是我所看到的一个例子:
INPUT
输入
echo $text;
OUTPUT
输出
База данни грешка.
INPUT
输入
json_encode($text);
OUTPUT
输出
"\u0411\u0430\u0437\u0430 \u0434\u0430\u043d\u043d\u0438 \u0433\u0440\u0435\u0448\u043a\u0430."
回答by John Severinson
Since PHP/5.4.0, there is an option called "JSON_UNESCAPED_UNICODE"
. Check it out:
从 PHP/5.4.0 开始,有一个名为"JSON_UNESCAPED_UNICODE"
. 一探究竟:
http://se2.php.net/json_encode
http://se2.php.net/json_encode
Therefore you should try:
因此,您应该尝试:
json_encode( $text, JSON_UNESCAPED_UNICODE );
回答by mpyw
JSON_UNESCAPED_UNICODE is available on PHP Version 5.4 or later.
The following code is for Version 5.3.
JSON_UNESCAPED_UNICODE 在 PHP 5.4 或更高版本上可用。
以下代码适用于 5.3 版。
UPDATED
更新
html_entity_decode
is a bit more efficient thanpack
+mb_convert_encoding
.(*SKIP)(*FAIL)
skips backslashes itself and specified characters byJSON_HEX_*
flags.
html_entity_decode
比pack
+效率更高一些mb_convert_encoding
。(*SKIP)(*FAIL)
跳过反斜杠本身和JSON_HEX_*
标志指定的字符。
function raw_json_encode($input, $flags = 0) {
$fails = implode('|', array_filter(array(
'\\',
$flags & JSON_HEX_TAG ? 'u003[CE]' : '',
$flags & JSON_HEX_AMP ? 'u0026' : '',
$flags & JSON_HEX_APOS ? 'u0027' : '',
$flags & JSON_HEX_QUOT ? 'u0022' : '',
)));
$pattern = "/\\(?:(?:$fails)(*SKIP)(*FAIL)|u([0-9a-fA-F]{4}))/";
$callback = function ($m) {
return html_entity_decode("&#x$m[1];", ENT_QUOTES, 'UTF-8');
};
return preg_replace_callback($pattern, $callback, json_encode($input, $flags));
}
回答by Adrian Romero
You like to set charset and unescaped unicode
您喜欢设置字符集和未转义的 unicode
header('Content-Type: application/json;charset=utf-8');
json_encode($data,JSON_UNESCAPED_UNICODE|JSON_PRETTY_PRINT);
回答by Steffo Dimfelt
One solution is to first encode data and then decode it in the same file:
一种解决方案是先对数据进行编码,然后在同一个文件中对其进行解码:
$string =json_encode($input, JSON_UNESCAPED_UNICODE) ;
echo $decoded = html_entity_decode( $string );
回答by gaba
Here is my combined solution for various PHP versions.
这是我针对各种 PHP 版本的组合解决方案。
In my company we are working with different servers with various PHP versions, so I had to find solution working for all.
在我的公司,我们正在使用具有各种 PHP 版本的不同服务器,因此我必须找到适合所有人的解决方案。
$phpVersion = substr(phpversion(), 0, 3)*1;
if($phpVersion >= 5.4) {
$encodedValue = json_encode($value, JSON_UNESCAPED_UNICODE);
} else {
$encodedValue = preg_replace('/\\u([a-f0-9]{4})/e', "iconv('UCS-4LE','UTF-8',pack('V', hexdec('U')))", json_encode($value));
}
Credits should go to Marco Gasi& abu. The solution for PHP >= 5.4 is provided in the json_encode docs.
学分应该去Marco Gasi& abu。PHP >= 5.4 的解决方案在 json_encode 文档中提供。
回答by abu
The raw_json_encode() function abovedid not solve me the problem (for some reason, the callback function raised an error on my PHP 5.2.5 server).
该raw_json_encode()函数上面并没有解决我的问题(由于某种原因,回调函数提出了我的PHP 5.2.5服务器上的错误)。
But this other solution did actually work.
但是这个其他解决方案确实有效。
https://www.experts-exchange.com/questions/28628085/json-encode-fails-with-special-characters.html
https://www.experts-exchange.com/questions/28628085/json-encode-fails-with-special-characters.html
Credits should go to Marco Gasi. I just call his function instead of calling json_encode():
学分应该去Marco Gasi。我只是调用他的函数而不是调用 json_encode():
function jsonRemoveUnicodeSequences( $json_struct )
{
return preg_replace( "/\\u([a-f0-9]{4})/e", "iconv('UCS-4LE','UTF-8',pack('V', hexdec('U')))", json_encode( $json_struct ) );
}
回答by Hoàng V? Tgtt
json_encode($text, JSON_UNESCAPED_UNICODE|JSON_UNESCAPED_SLASHES);
回答by Robin Carlo Catacutan
Since you asked:
既然你问:
Is there any way to convert the output to UTF-8 characters?
有没有办法将输出转换为 UTF-8 字符?
Another solution is to use utf8_encode.
另一种解决方案是使用utf8_encode。
This will encode your string to UTF-8
.
这会将您的字符串编码为UTF-8
.
e.g.
例如
foreach ($rows as $key => $row) {
$rows[$key]["keyword"] = utf8_encode($row["keyword"]);
}
echo json_encode($rows);
回答by JoakimH
Is this the expected behavior?
这是预期的行为吗?
the json_encode()
only works with UTF-8 encoded data.
将json_encode()
只适用于UTF-8编码的数据。
maybe you can get an answer to convert it here: cyrillic-characters-in-phps-json-encode
也许您可以在此处获得转换的答案:cyrillic-characters-in-phps-json-encode