java Gradle 本地项目依赖
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Gradle Local Project Dependency
提问by Josh M
I have 2 Gradle projects both inside the same directory. The directory structure is as follows:
我在同一个目录中有 2 个 Gradle 项目。目录结构如下：
ParentDirectory\
GradleProjectA\
build.gradle
GradleProjectB\
settings.gradle
build.gradle
I want to add GradleProjectAas a dependency to GradleProjectB. In the settings.gradlefor GradleProjectB, I've tried adding include 'GradleProjectA'and then in build.gradle: compile project(':GradleProjectA')but that didn't work.
我想GradleProjectA作为依赖添加到GradleProjectB. 在settings.gradlefor 中GradleProjectB，我尝试添加include 'GradleProjectA'然后添加build.gradle:compile project(':GradleProjectA')但这没有用。
Any help would be greatly appreciated. Thanks.
任何帮助将不胜感激。谢谢。
回答by Pavel Dudka
The way I did something like this is as follows:
我做这样的事情的方式如下：
GradleProjectB/settings.gradle:
GradleProjectB/settings.gradle：
include ':GradleProjectA'
project(':GradleProjectA').projectDir = new File('../GradleProjectA')
GradleProjectB/build.gradle:
GradleProjectB/build.gradle：
compile project(":GradleProjectA")
回答by Cosmin Ioni??
In the latest version of Gradle, you can use Composite Builds, like that:
在最新版本的 Gradle 中，您可以使用Composite Builds，如下所示：
In GradleProjectB's settings.gradle, add the following line:
在GradleProjectB 的 settings.gradle 中，添加以下行：
includeBuild "../GradleProjectA"
includeBuild "../GradleProjectA"
It will automatically handle dependency collisions and all that stuff.
它会自动处理依赖冲突和所有这些东西。
回答by bszeliga
The settings.gradle file needs to be in the parent directory specifying both.
settings.gradle 文件需要在指定两者的父目录中。
Try the following format:
尝试以下格式：
ParentDirectory\
build.gradle
settings.gradle <-- include 'GradleProjectA', 'GradleProjectB'
GradleProjectA/
build.gradle
GradleProjectB/
build.gradle
Edit: Ok if your Parent Directory is not a build directory then you can do the following:
编辑：好的，如果您的父目录不是构建目录，那么您可以执行以下操作：
in your gradle project b settings.gradle file try the following:
在您的 gradle 项目 b settings.gradle 文件中尝试以下操作：
includeFlat("GradleProjectA") // Include the project
in your b build.gradle:
在你的 b build.gradle 中：
compile project(":GradleProjectA")
回答by MonoThreaded
The following should do the trick:
以下应该可以解决问题：
root
+-- projectA
| +-- build.gradle
| => dependencies { compile project(':common') }
| +-- settings.gradle
| => include ':common'
| project(':common').projectDir = new File('../common')
+-- projectB
| => same as projectA
+-- common
+-- build.gradle
=> regular build, probably with a "jar" section
回答by Vampire
If GradleProjectAand GradleProjectBare part of one multi-project Gradle build, then you probably want the settings.gradlein ParentDirectoryand there include A and B. The way you use settings.gradleis not correct. Maybe you should re-read the section about multi-project gradle builds in the User Guide.
如果GradleProjectA和GradleProjectB是一个多项目摇篮构建的一部分，那么你可能想settings.gradle在ParentDirectory有包括A和B.您使用的方式settings.gradle是不正确的。也许您应该重新阅读用户指南中有关多项目 gradle 构建的部分。
If the two projects are indiviual projects but you still want to depend on A from B, you might prefer to build A, release it to some repository (possibly the mavenLocal repository) and then depend on the built artifacts from project B.
如果这两个项目是独立的项目，但您仍然希望从 B 依赖 A，您可能更喜欢构建 A，将其发布到某个存储库（可能是 mavenLocal 存储库），然后依赖于来自项目 B 的构建工件。
