使用 Jquery 更改表单输入值
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Change form input value with Jquery
提问by FlyingCat
I am trying to change the input field value dynamically when the user pick the options from my dropdown menu. I have tried this code but have no luck. I was wondering if someone here can help me out! Thanks a lot.
当用户从我的下拉菜单中选择选项时，我试图动态更改输入字段值。我试过这段代码，但没有运气。我想知道这里是否有人可以帮助我！非常感谢。
$(document).ready(function(){
$('select[name="job_number"]').change (function () {
$('input[name="project"]').val()="Good Fish";
});
});
<form action='project_manager' method='post'>
<input type='text' name='project'>show Good Fish when user picks an option</input>
<select name='job_number'>
<option value='1'>job1</option>
<option value='2'>job2</option>
<option value='3'>job3</option>
</select>
</form>
回答by aletzo
try :
尝试 ：
$('input[name="project"]').val("Good Fish");
instead of:
代替：
$('input[name="project"]').val()="Good Fish";
回答by Keith Frey
The code below should work. I modified the <input>in the html to be formatted correctly as well as changed $('input[name="project"]').val()="Good Fish";to $('input[name="project"]').val("Good Fish");
下面的代码应该可以工作。我<input>将 html 中的修改为正确格式并更改$('input[name="project"]').val()="Good Fish";为$('input[name="project"]').val("Good Fish");
$(document).ready(function(){
$('select[name="job_number"]').change(function() {
$('input[name="project"]').val("Good Fish");
});
});
<form action='project_manager' method='post'>
<input type='text' name='project' value='show Good Fish when user picks an option' />
<select name='job_number'>
<option value='1'>job1</option>
<option value='2'>job2</option>
<option value='3'>job3</option>
</select>
</form>
