Javascript ArrayBuffer 到 Blob 的转换

声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow 原文地址: http://stackoverflow.com/questions/44147912/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me): StackOverFlow

提示:将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间:2020-08-23 02:22:02  来源:igfitidea点击:

ArrayBuffer to blob conversion

javascriptdjvu

提问by Rulisp

I have a project where I need to display djvu schemas in browser.

我有一个项目需要在浏览器中显示 djvu 模式。

I found this old library on Githubwhich, as far as I understood, converts djvu files to bmp and then puts them into canvas element.

在 Github 上找到了这个旧,据我所知,它将 djvu 文件转换为 bmp,然后将它们放入画布元素中。

As I said, library is old(last commit was 5 years ago), so I need to make some corrections. Main problem is that lib uses obsolete BlobBuilder.

正如我所说,库很旧(上次提交是 5 年前),所以我需要做一些更正。主要问题是 lib 使用过时的 BlobBuilder。

Steps I made to solve this problem:

我为解决此问题而采取的步骤:

  1. Decompress this library via Chrome DevTools
  2. Initial error is at line 3774 var c = "undefined" != typeof MozBlobBuilder ? MozBlobBuilder : "undefined" != typeof WebKitBlobBuilder ? WebKitBlobBuilder : console.log("warning: cannot build blobs")
  3. I commented out this line
  4. Next, I commented out line c = new c;and some of following lines too.
  1. 通过 Chrome DevTools 解压这个库
  2. 初始错误在第 3774 行 var c = "undefined" != typeof MozBlobBuilder ? MozBlobBuilder : "undefined" != typeof WebKitBlobBuilder ? WebKitBlobBuilder : console.log("warning: cannot build blobs")
  3. 我注释掉了这一行
  4. 接下来,我也注释掉了 linec = new c;和一些以下几行。

So, now it looks this way(variable I is array buffer, and ololo1 and ololo2 are some kind of offset and limit)

所以,现在看起来是这样(变量 I 是数组缓冲区,而 ololo1 和 ololo2 是某种偏移和限制)

var c = new Blob(new Uint8Array(new Uint8Array(I,ololo1,ololo2)))
              , b = b.createObjectURL(c)
              , c = document.getElementById(kb)
              , f = c.getContext("2d")
              , h = new Image
              , g = a[Ea >> 2]
              , i = a[Fa >> 2]
              , j = c.width
              , k = Math.round(i * j / g);

            h.onload = function()
            {
                var a = g / j;
                4 < a && (a = 4);
                1 > a && (a = 1);
                f.globalAlpha = 1;

                for (N = 0; N < a; N++)
                    f.drawImage(h, N, N, g - a + N, i - a + N, 0, 0, j, k),
                    f.globalAlpha *= 1 - 1 / a;
                R(h.complete, "Image /bmp.bmp could not be decoded")
            }
            ;
            h.onerror = function(errorMsg, url, lineNumber, column, errorObj) {
                console.log(errorMsg, url, lineNumber, column, errorObj);
                console.log("Image /bmp.bmp could not be decoded!")
            }           
            ;

And now I stuck at error "Image /bmp.bmp could not be decoded!"(throwed in h.onerror handler).

现在我陷入了错误“无法解码图像 /bmp.bmp!”(抛出 h.onerror 处理程序)。

So, my question is: what I am doing wrong?

所以,我的问题是:我做错了什么?

回答by Kaiido

I don't know why the author did wrap his Uint8Arrayin an new one... note that I don't really know either the deprecated BlobBuilder API, but one typo I can see in your code is that you need to wrap your TypedArray in a normal Array:

我不知道作者为什么Uint8Array用一个新的包装他的......请注意,我真的不知道已弃用的 BlobBuilder API,但我在您的代码中看到的一个错字是您需要将 TypedArray 包装在一个普通的数组:

new Blob([new Uint8Array(buffer, byteOffset, length)]);

The Blob constructor takes a blobParts sequenceas first parameter, and then searches for BufferSource, USVStringsand Blobelements in this sequence. So when you pass a TypedArray, it will actually iterate over all the entries of this TypedArrayand treat these as USVString(and thus convert their numerical value to UTF-8 strings in the Blob). That's rarely what you want, so better always pass an Arrayin this constructor.

Blob 构造函数将blobParts 序列作为第一个参数,然后在此序列中搜索BufferSourceUSVStringsBlob元素。因此,当您传递TypedArray 时,它实际上会遍历此TypedArray 的所有条目并将它们视为USVString(从而将它们的数值转换为Blob中的 UTF-8 字符串)。这很少是你想要的,所以最好总是在这个构造函数中传递一个数组

回答by xsilen T

var buffer = new ArrayBuffer(32);

new Blob([buffer]);

so the Uint8Array should be

所以 Uint8Array 应该是

new Blob([new Uint8Array([1, 2, 3, 4]).buffer]);