Java Spring MVC：如何返回自定义 404 错误页面？
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/21061638/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Spring MVC: How to return custom 404 errorpages?
提问by Christian Rudolph
I'm looking for a clean way to return customized 404 errorpages in Spring 4 when a requested resource was not found. Queries to different domain types should result in different error pages.
当找不到请求的资源时，我正在寻找一种干净的方法来在 Spring 4 中返回自定义的 404 错误页面。对不同域类型的查询应该会导致不同的错误页面。
Here some code to show my intention (Meter is a domain class):
这里有一些代码来显示我的意图（Meter 是一个域类）：
@RequestMapping(value = "/{number}", method = RequestMethod.GET)
public String getMeterDetails(@PathVariable("number") final Long number, final Model model) {
final Meter result = meterService.findOne(number);
if (result == null) {
// here some code to return an errorpage
}
model.addAttribute("meter", result);
return "meters/details";
}
I imagine several ways for handling the problem. First there would be the possibility to create RuntimeExceptions like
我想象了几种处理问题的方法。首先将有可能创建RuntimeException像
@ResponseStatus(HttpStatus.NOT_FOUND)
public class MeterNotFoundExcption extends RuntimeException { }
and then use an exception handler to render a custom errorpage (maybe containing a link to a list of meters or whatever is appropriate).
然后使用异常处理程序呈现自定义错误页面（可能包含指向仪表列表或任何适当内容的链接）。
But I don't like polluting my application with many small exceptions.
但我不喜欢用许多小的例外来污染我的应用程序。
Another possibility would be using HttpServletResponseand set the statuscode manually:
另一种可能性是HttpServletResponse手动使用和设置状态码：
@RequestMapping(value = "/{number}", method = RequestMethod.GET)
public String getMeterDetails(@PathVariable("number") final Long number, final Model model,
final HttpServletResponse response) {
final Meter meter = meterService.findOne(number);
if (meter == null) {
response.setStatus(HttpStatus.NOT_FOUND.value());
return "meters/notfound";
}
model.addAttribute("meter", meter);
return "meters/details";
}
But with this solution I have to duplicate the first 5 lines for many controller methods (like edit, delete).
但是使用此解决方案，我必须为许多控制器方法（如编辑、删除）复制前 5 行。
Is there an elegant way to prevent duplicating these lines many times?
有没有一种优雅的方法来防止多次重复这些行？
采纳答案by Christian Rudolph
The solution is much simpler than thought. One can use one generic ResourceNotFoundExceptiondefined as follows:
解决方案比想象的要简单得多。可以使用一种ResourceNotFoundException定义如下的泛型：
public class ResourceNotFoundException extends RuntimeException { }
then one can handle errors within every controller with an ExceptionHandlerannotation:
然后可以使用ExceptionHandler注释处理每个控制器中的错误：
class MeterController {
// ...
@ExceptionHandler(ResourceNotFoundException.class)
@ResponseStatus(HttpStatus.NOT_FOUND)
public String handleResourceNotFoundException() {
return "meters/notfound";
}
// ...
@RequestMapping(value = "/{number}/edit", method = RequestMethod.GET)
public String viewEdit(@PathVariable("number") final Meter meter,
final Model model) {
if (meter == null) throw new ResourceNotFoundException();
model.addAttribute("meter", meter);
return "meters/edit";
}
}
Every controller can define its own ExceptionHandlerfor the ResourceNotFoundException.
每个控制器都可ExceptionHandler以为ResourceNotFoundException.
回答by Youddh
modified your web.xmlfile.Using following code.
修改了您的web.xml文件。使用以下代码。
<display-name>App Name </display-name>
<error-page>
<error-code>500</error-code>
<location>/error500.jsp</location>
</error-page>
<error-page>
<error-code>404</error-code>
<location>/error404.jsp</location>
</error-page>
Access this by following code.
通过以下代码访问它。
response.sendError(508802,"Error Message");
Now add this code in web.xml.
现在在web.xml 中添加此代码。
<error-page>
<error-code>508802</error-code>
<location>/error500.jsp</location>
</error-page>
回答by Taras
You should follow this article where you can find detailed information about exception handling in Spring MVC projects.
您应该遵循这篇文章，在那里您可以找到有关 Spring MVC 项目中异常处理的详细信息。
@ControllerAdvice may help you in this case
在这种情况下@ControllerAdvice 可能会帮助你
回答by Ekansh Rastogi
You can map the error codes in web.xml like the following
您可以像下面这样映射 web.xml 中的错误代码
<error-page>
<error-code>400</error-code>
<location>/400</location>
</error-page>
<error-page>
<error-code>404</error-code>
<location>/404</location>
</error-page>
<error-page>
<error-code>500</error-code>
<location>/500</location>
</error-page>
Now you can create a controller to map the url's that are hit when any of these error is found.
现在您可以创建一个控制器来映射在发现任何这些错误时命中的 url。
@Controller
public class HTTPErrorHandler{
String path = "/error";
@RequestMapping(value="/404")
public String error404(){
// DO stuff here
return path+"/404";
}
}
For full example see my tutorial about this
有关完整示例，请参阅我的教程
回答by Manoj Kumar
We can just add following lines of code into web.xml file and introduce a new jsp file named errorPage.jsp into root directory of the project to get the requirement done.
我们只需在web.xml文件中添加以下几行代码，并在项目的根目录中引入一个名为errorPage.jsp的新jsp文件即可完成需求。
<error-page>
<error-code>400</error-code>
<location>/errorPage.jsp</location>
</error-page>
<error-page>
<error-code>404</error-code>
<location>/errorPage.jsp</location>
</error-page>
<error-page>
<error-code>500</error-code>
<location>/errorPage.jsp</location>
</error-page>
回答by SerdukovAA
Simple answer for 100% free xml:
100% 免费 xml 的简单答案：
Set properties for DispatcherServlet
public class SpringMvcInitializer extends AbstractAnnotationConfigDispatcherServletInitializer { @Override protected Class<?>[] getRootConfigClasses() { return new Class[] { RootConfig.class }; } @Override protected Class<?>[] getServletConfigClasses() { return new Class[] {AppConfig.class }; } @Override protected String[] getServletMappings() { return new String[] { "/" }; } //that's important!! @Override protected void customizeRegistration(ServletRegistration.Dynamic registration) { boolean done = registration.setInitParameter("throwExceptionIfNoHandlerFound", "true"); // -> true if(!done) throw new RuntimeException(); }}
Create @ControllerAdvice:
@ControllerAdvice public class AdviceController { @ExceptionHandler(NoHandlerFoundException.class) public String handle(Exception ex) { return "redirect:/404"; } @RequestMapping(value = {"/404"}, method = RequestMethod.GET) public String NotFoudPage() { return "404"; }}
Create 404.jsp page with any content
设置 DispatcherServlet 的属性
public class SpringMvcInitializer extends AbstractAnnotationConfigDispatcherServletInitializer { @Override protected Class<?>[] getRootConfigClasses() { return new Class[] { RootConfig.class }; } @Override protected Class<?>[] getServletConfigClasses() { return new Class[] {AppConfig.class }; } @Override protected String[] getServletMappings() { return new String[] { "/" }; } //that's important!! @Override protected void customizeRegistration(ServletRegistration.Dynamic registration) { boolean done = registration.setInitParameter("throwExceptionIfNoHandlerFound", "true"); // -> true if(!done) throw new RuntimeException(); }}
创建@ControllerAdvice：
@ControllerAdvice public class AdviceController { @ExceptionHandler(NoHandlerFoundException.class) public String handle(Exception ex) { return "redirect:/404"; } @RequestMapping(value = {"/404"}, method = RequestMethod.GET) public String NotFoudPage() { return "404"; }}
创建包含任何内容的 404.jsp 页面
That's all.
就这样。
回答by skrueger
I also needed to NOT use org.springframework.web.servlet.config.annotation.DefaultServletHandlerConfigurer.
我还需要不使用org.springframework.web.servlet.config.annotation.DefaultServletHandlerConfigurer.
According to org.springframework.web.servlet.DispatcherServlet.setThrowExceptionIfNoHandlerFound(boolean): "Note that if DefaultServletHttpRequestHandler is used, then requests will always be forwarded to the default servlet and a NoHandlerFoundException would never be thrown in that case."
根据org.springframework.web.servlet.DispatcherServlet.setThrowExceptionIfNoHandlerFound(boolean)：“请注意，如果使用 DefaultServletHttpRequestHandler，则请求将始终转发到默认 servlet，并且在这种情况下永远不会抛出 NoHandlerFoundException。”
Before
前
@Configuration
@EnableWebMvc
@ComponentScan(basePackages = "com.foo.web")
public class WebMvcConfiguration extends WebMvcConfigurerAdapter {
@Override
public void configureDefaultServletHandling(DefaultServletHandlerConfigurer configurer) {
configurer.enable();
}
// ...
}
After
后
@Configuration
@EnableWebMvc
@ComponentScan(basePackages = "com.foo.web")
public class WebMvcConfiguration extends WebMvcConfigurerAdapter {
@Override
public void configureDefaultServletHandling(DefaultServletHandlerConfigurer configurer) {
}
// ...
}
回答by Yasitha Bandara
I'm working with a Netbeans project.I added following lines to my web.xml.It only works when I give the path from WEB-INF folder as follows.
我正在处理一个 Netbeans 项目。我在我的 web.xml 中添加了以下几行。它仅在我提供来自 WEB-INF 文件夹的路径时才有效，如下所示。
<error-page>
<error-code>404</error-code>
<location>/WEB-INF/view/common/errorPage.jsp</location>
</error-page>
