在 Python 中将整数转换为 2 字节的十六进制值
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Convert an integer to a 2 byte Hex value in Python
提问by Brett Prudhom
For a tkinter GUI, I must read in a Hex address in the form of '0x00' to set an I2C address. The way I am currently doing it is by reading the input as a string, converting the string to an integer, then converting that integer to an actual Hex value as shown in the partial code below:
对于 tkinter GUI，我必须以“0x00”的形式读取十六进制地址以设置 I2C 地址。我目前的做法是将输入作为字符串读取，将字符串转换为整数，然后将该整数转换为实际的十六进制值，如下面的部分代码所示：
GUI initialization:
图形界面初始化：
self.I2CAddress=StringVar()
self.I2CAddress.set("0x00") #Sets Default value of '0x00'
Label(frame, text="Address: ").grid(row=5, column=4)
Entry(frame, textvariable=self.I2CAddress).grid(row=5, column=5)
Then inside the function:
然后在函数内部：
addr = self.I2CAddress.get()
addrint = int(addr, 16)
addrhex = hex(addrint)
This works for most values, but my issue is that if I enter a small Hex value string such as '0x01', it converts to the proper integer of 1, but then that is converted to a Hex value of 0x1 instead of 0x01.
这适用于大多数值，但我的问题是，如果我输入一个小的十六进制值字符串，例如“0x01”，它会转换为正确的整数 1，但随后会转换为十六进制值 0x1 而不是 0x01。
I am an EE and have very limited programming experience, so any help is greatly appreciated.
我是一名 EE，编程经验非常有限，因此非常感谢任何帮助。
采纳答案by Martijn Pieters
Use the format()function:
使用format()功能：
format(addrint, '#04x')
This formats the input value as a 2 digit hexadecimal string with leading zeros to make up the length, and #includes the 'standard prefix', 0xin this case. Note that the width of 4 includes that prefix. xproduces lower-case hex strings; use Xif you need uppercase.
这将输入值格式化为带有前导零的 2 位十六进制字符串以构成长度，并且在这种情况下#包括“标准前缀” 0x。请注意，宽度 4 包括该前缀。x产生小写的十六进制字符串；使用X如果您需要大写。
Demo:
演示：
>>> for i in range(8, 12):
... print format(i, '#04x')
...
0x08
0x09
0x0a
0x0b
