node.js mongodb/mongoose findMany - 查找 ID 列在数组中的所有文档
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mongodb/mongoose findMany - find all documents with IDs listed in array
提问by ezmilhouse
I have an array of _ids and I want to get all docs accordingly, what's the best way to do it ?
我有一个 _id 数组,我想相应地获取所有文档,最好的方法是什么?
Something like ...
就像是 ...
// doesn't work ... of course ...
model.find({
'_id' : [
'4ed3ede8844f0f351100000c',
'4ed3f117a844e0471100000d',
'4ed3f18132f50c491100000e'
]
}, function(err, docs){
console.log(docs);
});
The array might contain hundreds of _ids.
该数组可能包含数百个 _id。
回答by Daniel Mendel
The findfunction in mongoose is a full query to mongoDB. This means you can use the handy mongoDB $inclause, which works just like the SQL version of the same.
findmongoose 中的函数是对 mongoDB 的完整查询。这意味着您可以使用方便的 mongoDB$in子句,它的工作方式与 SQL 版本相同。
model.find({
'_id': { $in: [
mongoose.Types.ObjectId('4ed3ede8844f0f351100000c'),
mongoose.Types.ObjectId('4ed3f117a844e0471100000d'),
mongoose.Types.ObjectId('4ed3f18132f50c491100000e')
]}
}, function(err, docs){
console.log(docs);
});
This method will work well even for arrays containing tens of thousands of ids. (See Efficiently determine the owner of a record)
即使对于包含数万个 id 的数组,这种方法也能很好地工作。(请参阅有效确定记录的所有者)
I would recommend that anybody working with mongoDBread through the Advanced Queriessection of the excellent Official mongoDB Docs
我建议任何工作的人mongoDB通读优秀的官方 mongoDB 文档的高级查询部分
回答by SnnSnn
Ids is the array of object ids:
Ids 是对象 ID 的数组:
const ids = [
'4ed3ede8844f0f351100000c',
'4ed3f117a844e0471100000d',
'4ed3f18132f50c491100000e',
];
Using Mongoose with callback:
使用带有回调的猫鼬:
Model.find().where('_id').in(ids).exec((err, records) => {});
Using Mongoose with async function:
使用具有异步功能的猫鼬:
records = await Model.find().where('_id').in(ids).exec();
Don't forget to change Model with your actual model.
不要忘记使用您的实际模型更改模型。
回答by Derese Getachew
Use this format of querying
使用这种查询格式
let arr = _categories.map(ele => new mongoose.Types.ObjectId(ele.id));
Item.find({ vendorId: mongoose.Types.ObjectId(_vendorId) , status:'Active'})
.where('category')
.in(arr)
.exec();
回答by Nico
Both node.js and MongoChef force me to convert to ObjectId. This is what I use to grab a list of users from the DB and fetch a few properties. Mind the type conversion on line 8.
node.js 和 MongoChef 都强迫我转换为 ObjectId。这是我用来从数据库中获取用户列表并获取一些属性的方法。注意第 8 行的类型转换。
// this will complement the list with userName and userPhotoUrl based on userId field in each item
augmentUserInfo = function(list, callback){
var userIds = [];
var users = []; // shortcut to find them faster afterwards
for (l in list) { // first build the search array
var o = list[l];
if (o.userId) {
userIds.push( new mongoose.Types.ObjectId( o.userId ) ); // for the Mongo query
users[o.userId] = o; // to find the user quickly afterwards
}
}
db.collection("users").find( {_id: {$in: userIds}} ).each(function(err, user) {
if (err) callback( err, list);
else {
if (user && user._id) {
users[user._id].userName = user.fName;
users[user._id].userPhotoUrl = user.userPhotoUrl;
} else { // end of list
callback( null, list );
}
}
});
}

