C语言 在 C 中创建一个 int 数组数组？
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Creating an array of int arrays in C?
提问by Eric Brotto
Let us say I have the following method prototype:
假设我有以下方法原型：
void mix_audio(int *vocal_data_array, int *instrumental_data_array, int *mixed_audio_array, FOURTH ARGUMENT)
{
}
How would I:
我将如何：
Initialize an array_of_arrays before the above argument so as to pass it as the fourth argument?
In the method, make it so that the first value of my array_of_arrays is the array called vocal_data, that the second value of my array is instrumental_data_array and the third value is mixed_audio_array.
How would I later then loop through all the values of the first array within the array_of_arrays.
在上述参数之前初始化一个 array_of_arrays 以便将它作为第四个参数传递？
在该方法中，使我的array_of_arrays 的第一个值是称为vocal_data 的数组，我的数组的第二个值是instrumental_data_array，第三个值是mixed_audio_array。
稍后我将如何遍历 array_of_arrays 中第一个数组的所有值。
I hope I'm not asking too much here. I just thought it would be simple syntax that someone could spit out pretty quickly :)
我希望我不要在这里要求太多。我只是认为这是一个简单的语法，有人可以很快吐出来:)
Thanks!
谢谢！
EDIT 1
编辑 1
Please note that although I've showed by my example an array_of_arrays of length 3 I'm actually looking to create something that could contain a variable length of arrays.
请注意，虽然我已经通过我的示例展示了一个长度为 3 的 array_of_arrays，但我实际上是想创建一些可以包含可变长度数组的东西。
回答by jmq
Simple array of arrays and a function showing how to pass it. I just added fake values to the arrays to show that something was passed to the function and that I could print it back out. The size of the array, 3, is just arbitrary and can be changed to whatever sizing you want. Each array can be of a different size (known as a jagged array). It shows your three criteria:
简单的数组数组和一个显示如何传递它的函数。我只是在数组中添加了假值，以显示某些内容已传递给函数，并且我可以将其打印出来。数组的大小 3 是任意的，可以更改为您想要的任何大小。每个数组可以有不同的大小（称为锯齿状数组）。它显示了您的三个标准：
Initialization, Assigning values to each index of arrayOfArrays, The function demonstrates how to extract the data from the array of arrays
初始化，为 的每个索引赋值arrayOfArrays，函数演示如何从数组中提取数据
#include <stdio.h>
void mix_audio(int *arr[3]);
int main() {
int *arrayOfArrays[3];
int vocal[3] = {1,2,3};
int instrumental[3] = {4,5,6};
int mixed_audio[3] = {7,8,9};
arrayOfArrays[0] = vocal;
arrayOfArrays[1] = instrumental;
arrayOfArrays[2] = mixed_audio;
mix_audio(arrayOfArrays);
return(0);
}
void mix_audio(int *arr[3]) {
int i;
int *vocal = arr[0];
int *instrumental = arr[1];
int *mixed_audio = arr[2];
for (i=0; i<3; i++) {
printf("vocal = %d\n", vocal[i]);
}
for (i=0; i<3; i++) {
printf("instrumental = %d\n", instrumental[i]);
}
for (i=0; i<3; i++) {
printf("mixed_audio = %d\n", mixed_audio[i]);
}
}
回答by GrahamS
From your question it sounds like you actually want a structcontaining your arrays, something like:
从您的问题听起来，您实际上想要一个struct包含您的数组，例如：
struct AudioData {
int* vocal_data_array;
unsigned int vocal_data_length;
int* instrumental_data_array;
unsigned int instrumental_data_length;
int* mixed_audio_array;
unsigned int mixed_audio_length;
};
回答by hennes
For the array allocation using the example of an array of integers:
对于使用整数数组示例的数组分配：
int** x = malloc (sizeof (int*) * rows);
if (! x) {
// Error
}
for (int i = 0; i < rows; ++i) {
x[i] = malloc (sizeof (int) * columns);
if (! x[i]) {
// Error
}
}
