javascript 如何在通过 .ajaxForm() 提交表单之前执行一些操作？
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how to perform some action before submit form via .ajaxForm()?
提问by Uday A. Navapara
i am using ajaxForm() frame work to send my data without reloading my page.
我正在使用 ajaxForm() 框架工作来发送我的数据而无需重新加载我的页面。
$('#ReplayForm').ajaxForm({
success : function(data){
alert("Success");
}
});
now, i want to check some condition before submitting the form and if the condition is false then stop submission else continue.
现在，我想在提交表单之前检查一些条件，如果条件为假，则停止提交，否则继续。
is there any solution to do this work or is there any way buy which i can perform this operation. Thanks in advance.
是否有任何解决方案可以完成这项工作，或者有什么方法可以购买我可以执行此操作的方法。提前致谢。
回答by Ashish Vaghasiya
Yes, definatly you can handle this situation. you have to call beforesubmit method for this let see one example
是的，您绝对可以处理这种情况。你必须为此调用 beforesubmit 方法让我们看一个例子
$('#ReplayForm').ajaxForm({
beforeSubmit : function(arr, $form, options){
if("condition is true")
{
return true; //it will continue your submission.
}
else
{
return false; //ti will stop your submission.
}
},
success : function(data){
endLoading();
if(data.result=="success")
{
showSuccessNotification(data.notification);
}
else
{
showErrorNotification(data.notification);
}
}
});
回答by Arun P Johny
You can use the beforeSubmitoption
您可以使用beforeSubmit选项
$('#ReplayForm').ajaxForm({
beforeSubmit: function (arr, $form, options) {
//check your conditions and return false to prevent the form submission
if (!valid) {
return false;
}
},
success: function (data) {
alert("Success");
}
});
回答by Edward
Use beforeSendoption in JQuery AJAX framework, if the test fails return falseshould do it.
beforeSend在 JQuery AJAX 框架中使用选项，如果测试失败return false应该这样做。
$('#ReplayForm').ajaxForm({
success : function(data){
alert("Success");
},
beforeSend: function() {
if(!myFunc()) {
return false;
}
}
});
