Oracle SQL Where 子句查找超过 30 天的日期记录
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Oracle SQL Where clause to find date records older than 30 days
提问by anwarma
I want to find records in a (Oracle SQL) table using the creation date field where records are older than 30 days. It would be nice to find records using a operators like > but if anyone can suggest quick SQL where clause statement to find records older than 30 days that would be nice. Please suggest Oracle syntax as that is what I am using.
我想使用记录超过 30 天的创建日期字段在（Oracle SQL）表中查找记录。使用像 > 这样的运算符查找记录会很好，但是如果有人可以建议使用快速 SQL where 子句语句来查找超过 30 天的记录，那就太好了。请建议 Oracle 语法，因为这是我正在使用的。
回答by OMG Ponies
Use:
用：
SELECT *
FROM YOUR_TABLE
WHERE creation_date <= TRUNC(SYSDATE) - 30
SYSDATE returns the date & time; TRUNCresets the date to being as of midnight so you can omit it if you want the creation_datethat is 30 days previous including the current time.
SYSDATE 返回日期和时间；TRUNC将日期重置为午夜，因此如果您想要creation_date包括当前时间在内的 30 天前的日期，则可以省略它。
Depending on your needs, you could also look at using ADD_MONTHS:
根据您的需要，您还可以考虑使用ADD_MONTHS：
SELECT *
FROM YOUR_TABLE
WHERE creation_date <= ADD_MONTHS(TRUNC(SYSDATE), -1)
