bash sed 意外字符

sed unexpected character

提问by Ahmed Waheed

I'm writing the following script:

我正在编写以下脚本：

v="1,pop";
sed "$v/d" dir/file1

It gives me this error:

它给了我这个错误：

char 3: unexpected `,'

How to solve this? Note: the value of $vcannot be controlled.

如何解决这个问题？注意： 的值$v无法控制。

采纳答案by Suku

You are using sedin a wrong way.

你用sed错了方法。

$ v="1,pop";
$ cat file 
1,pop
Suku
JohnGeorge
stackoverflow
serverfault

$ sed '/'$v'/d' file
Suku
JohnGeorge
stackoverflow
serverfault

$ sed "/"$v"/d" file
Suku
JohnGeorge
stackoverflow
serverfault

If you want to substitute a bash variable inside sed, you need to surround it with quotes like I showed above. Also if you want to write modification to file, you need to use sedwith -i.

如果你想在里面替换一个 bash 变量sed，你需要用我上面展示的引号将它括起来。此外，如果您想将修改写入文件，则需要使用sedwith -i。

回答by vara

Using this way in script

在脚本中使用这种方式

v="1,pop"

v="1,流行"

sed "/^$v$/{

sed "/^$v$/{

d

d

}" dir/file1

}"目录/文件1

回答by alex

You need the hashbangso your shell knows how to execute the script.

您需要hashbang以便您的 shell 知道如何执行脚本。

#!/bin/sh

Then you'll get...

然后你会得到...

sed: 1: "1,pop/d": expected context address

sed: 1: "1,pop/d": 预期的上下文地址

...which tells your the commands were executed. :)

...它告诉您命令已执行。:)