string Jinja 中的字符串连接
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String concatenation in Jinja
提问by KacieHouser
I just want to loop through an existing list and make a comma delimited string out of it.
Something like this: my_string = 'stuff, stuff, stuff, stuff'
我只想遍历现有列表并从中生成一个逗号分隔的字符串。
像这样的东西:my_string = 'stuff, stuff, stuff, stuff'
I already know about loop.last
, I just need to know how to make the third line in my code below WORK.
我已经知道了loop.last
,我只需要知道如何使代码中的第三行在 WORK 下面。
{% set my_string = '' %}
{% for stuff in stuffs %}
{% set my_string = my_string + stuff + ', '%}
{% endfor%}
回答by mechanical_meat
回答by Dag Wieers
You can use +
if you know all the values are strings. Jinja also provides the ~
operator, which will ensure all values are converted to string first.
+
如果您知道所有值都是字符串,则可以使用。Jinja 还提供了~
运算符,它将确保所有值首先转换为字符串。
{% set my_string = my_string ~ stuff ~ ', '%}
回答by KacieHouser
My bad, in trying to simplify it, I went too far, actually stuffs
is a record of all kinds of info, I just want the id in it.
我的不好,为了简化它,我走得太远了,实际上stuffs
是各种信息的记录,我只是想要其中的id。
stuffs = [[123, first, last], [456, first, last]]
I want my_sting
to be
我想my_sting
成为
my_sting = '123, 456'
My original code should have looked like this:
我的原始代码应该是这样的:
{% set my_string = '' %}
{% for stuff in stuffs %}
{% set my_string = my_string + stuff.id + ', '%}
{% endfor%}
Thinking about it, stuffs
is probably a dictionary, but you get the gist.
想想看,stuffs
可能是一本字典,但你明白了要点。
Yes I found the join
filter, and was going to approach it like this:
是的,我找到了join
过滤器,并打算像这样处理它:
{% set my_string = [] %}
{% for stuff in stuffs %}
{% do my_string.append(stuff.id) %}
{% endfor%}
{% my_string|join(', ') %}
But the append doesn't work without importing the extensions to do it, and reading that documentation gave me a headache. It doesn't explicitly say where to import it from or even where you would put the import statement, so I figured finding a way to concat would be the lesser of the two evils.
但是如果不导入扩展名,附加就无法工作,阅读该文档让我很头疼。它没有明确说明从哪里导入它,甚至没有说明将 import 语句放在哪里,所以我认为找到一种连接方法是两害相权取其轻。
回答by Kapil
Just another hack can be like this.
只是另一个黑客可能是这样的。
I have Array of strings which I need to concatenate. So I added that array into dictionary and then used it inside for loop which worked.
我有需要连接的字符串数组。所以我将该数组添加到字典中,然后在有效的 for 循环中使用它。
{% set dict1 = {'e':''} %}
{% for i in list1 %}
{% if dict1.update({'e':dict1.e+":"+i+"/"+i}) %} {% endif %}
{% endfor %}
{% set layer_string = dict1['e'] %}
回答by Jakub N
If you can't just use filter join but need to perform some operations on the array's entry:
如果您不能只使用过滤器连接而是需要对数组的条目执行一些操作:
{% for entry in array %}
User {{ entry.attribute1 }} has id {{ entry.attribute2 }}
{% if not loop.last %}, {% endif %}
{% endfor %}