php 如何调用作为类变量的闭包?
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How to call a closure that is a class variable?
提问by rsk82
class MyClass {
var $lambda;
function __construct() {
$this->lambda = function() {echo 'hello world';};
// no errors here, so I assume that this is legal
}
}
$myInstance = new MyClass();
$myInstance->lambda();
//Fatal error: Call to undefined method MyClass::lambda()
So what is the correct syntax for reaching class variables ?
那么达到类变量的正确语法是什么?
回答by Arnaud Le Blanc
In PHP, methods and properties are in a separate namespace (you can have a method and a property with the same name), and whether you are accessing a property or a method depends of the syntax you are using to do so.
在 PHP 中,方法和属性位于单独的命名空间中(您可以拥有同名的方法和属性),并且您是访问属性还是方法取决于您使用的语法。
$expr->something()is a method call, so PHP will search somethingin the class' list of methods.
$expr->something()是一个方法调用,所以 PHP 将something在类的方法列表中搜索。
$expr->somethingis a property fetch, so PHP will search somethingin the class' list of properties.
$expr->something是一个属性获取,所以 PHP 将something在类的属性列表中搜索。
$myInstance->lambda();is parsed as a method call, so PHP searches for a method named lambdain your class, but there is no such method (hence the Call to undefined methoderror).
$myInstance->lambda();被解析为方法调用,因此 PHP 搜索lambda在您的类中命名的方法,但没有这样的方法(因此调用未定义的方法错误)。
So you have to use the fetch propertysyntax to fetch the lambda, and then call it.
所以你必须使用fetch 属性语法来获取 lambda,然后调用它。
Since PHP 7.0, you can do this with
($obj->lambda)():($obj->lambda)();The parentheses make sure that PHP parses
($obj->lambda)as fetch the property named lambda. Then,()calls the result of fetching the property.or you can do this with
->lambda->__invoke():$myInstance = new MyClass(); $myInstance->lambda->__invoke();__invokeis one of PHP's magic methods. When an object implements this method, it becomes invokable: it can be called using the$var()syntax. Anonymous functions are instances ofClosure, which implements__invoke.Or assign it to a local variable:
$lambda = $myInstance->lambda; $lambda();Or call it using call_user_func:
call_user_func($myInstance->lambda);call_user_funccan call anycallable, including anonymous functions.Alternatively, if this is a common pattern in your code, you can setup a
__callmethod to forward calls to your lambda:class MyClass { private $lambda; public function __construct() { $this->lambda = function() { echo "Hello world!\n"; }; } public function __call($name, $args) { return call_user_func_array($this->$name, $args); } }Now this works:
$myInstance = new MyClass(); $myInstance->lambda();Since PHP 5.4 you can even do that in a trait:
trait LambdasAsMethods { public function __call($name, $args) { return call_user_func_array($this->$name, $args); } } class MyClass { use LambdasAsMethods; private $lambda; public function __construct() { $this->lambda = function() { echo "Hello World!\n"; }; } } $myInstance = new MyClass(); $myInstance->lambda();
从 PHP 7.0 开始,您可以使用以下命令执行此操作
($obj->lambda)():($obj->lambda)();括号确保 PHP 解析
($obj->lambda)为获取名为 lambda 的属性。然后,()调用获取属性的结果。或者你可以这样做
->lambda->__invoke():$myInstance = new MyClass(); $myInstance->lambda->__invoke();__invoke是PHP 的神奇方法之一。当一个对象实现这个方法时,它变得可调用:它可以使用$var()语法调用。匿名函数是 的实例Closure,它实现__invoke.或者将其分配给局部变量:
$lambda = $myInstance->lambda; $lambda();或者使用 call_user_func 调用它:
call_user_func($myInstance->lambda);call_user_func可以调用 anycallable,包括匿名函数。或者,如果这是您代码中的常见模式,您可以设置一个
__call方法来将调用转发到您的 lambda:class MyClass { private $lambda; public function __construct() { $this->lambda = function() { echo "Hello world!\n"; }; } public function __call($name, $args) { return call_user_func_array($this->$name, $args); } }现在这有效:
$myInstance = new MyClass(); $myInstance->lambda();从 PHP 5.4 开始,您甚至可以在 trait 中做到这一点:
trait LambdasAsMethods { public function __call($name, $args) { return call_user_func_array($this->$name, $args); } } class MyClass { use LambdasAsMethods; private $lambda; public function __construct() { $this->lambda = function() { echo "Hello World!\n"; }; } } $myInstance = new MyClass(); $myInstance->lambda();
回答by akDeveloper
You can also call your lambda function without change something in your class, using ReflectionFunction.
您还可以使用 ReflectionFunction 调用 lambda 函数,而无需更改类中的某些内容。
$myInstance = new MyClass();
$lambda = new ReflectionFunction($myInstance->lambda);
$lambda->invoke();
or if you have to pass arguments then
或者如果你必须传递参数,那么
$args = array('arg'=>'value');
$lambda->invokeArgs($args);

