ios 带有逗号小数分隔符的 NSNumberFormatter

NSNumberFormatter with comma decimal separator

提问by Pierre

I tried to convert an NSString like "12000.54" into "12.000,54". I wrote an NSNumberFormatter instance.

我试图将像“12000.54”这样的 NSString 转换为“12.000,54”。我写了一个 NSNumberFormatter 实例。

NSNumberFormatter *formatter = [[[NSNumberFormatter alloc] init] autorelease];
[formatter setFormatterBehavior:NSNumberFormatterBehavior10_4];
[formatter setNumberStyle:NSNumberFormatterDecimalStyle];
[formatter setGroupingSeparator:@"."];
[formatter setDecimalSeparator:@","];

But when I NSLog this :

但是当我 NSLog 这个：

NSLog(@"%@",[formatter stringFromNumber:[formatter numberFromString:value]]);

It prints null value. If I change my comma with a point it's working correctly. I just would like to be able to put what I want for my separators field (comma, point, slash, etc ...) and I have different outputs : 12/000,54 12.000.54 12,000,54 for example.

它打印空值。如果我用一个点更改我的逗号，它就可以正常工作。我只是希望能够为我的分隔符字段（逗号、点、斜线等）输入我想要的内容，并且我有不同的输出：例如 12/000,54 12.000.54 12,000,54。

Do you know how I can handle this ?

你知道我怎么处理吗？

回答by JFS

I would recommend not hardcoding the separator to ensure the right separator behavior based on the iPhone locale setting. The easiest way to to this is:

我建议不要对分隔符进行硬编码，以确保根据 iPhone 语言环境设置正确的分隔符行为。最简单的方法是：

using objective-c

使用目标-c

NSNumberFormatter *numberFormatter = [[NSNumberFormatter alloc]init];
numberFormatter.locale = [NSLocale currentLocale];// this ensures the right separator behavior
numberFormatter.numberStyle = NSNumberFormatterDecimalStyle;
numberFormatter.usesGroupingSeparator = YES;

// example for writing the number object into a label
cell.finalValueLabel.text = [NSString StringWithFormat:@"%@", [numberFormatter stringForObjectValue:numberFromString]]; // your var name is not well chosen

using SWIFT 3

使用 SWIFT 3

 let formatter = NumberFormatter()
 formatter.locale = NSLocale.current // this ensures the right separator behavior
 formatter.numberStyle = NumberFormatter.Style.decimal
 formatter.usesGroupingSeparator = true

 // example for writing the number object into a label
 // your variable "numberFromString" needs to be a NSNumber object
 finalValueLabel.text = formatter.string(from: numberFromString)! // your var name is not well chosen

and I would not use the var-name "numberFromString" because it is an NSNumberFormattermethod. Good luck!

我不会使用 var-name "numberFromString" 因为它是一种NSNumberFormatter方法。祝你好运！

回答by Pierre

So the question is valid : I'm answering it myself :)

所以这个问题是有效的：我自己回答:)

I have a decimal value read from sqlite (e.g 12000 or 12000.54) directly transformed into NSString. I have to use different separator at some point in my code.

我有一个从 sqlite（例如 12000 或 12000.54）读取的十进制值直接转换为 NSString。我必须在代码中的某个时候使用不同的分隔符。

NSNumberFormatter *formatter = [[[NSNumberFormatter alloc] init] autorelease];
[formatter setFormatterBehavior:NSNumberFormatterBehavior10_4];
[formatter setNumberStyle:NSNumberFormatterDecimalStyle];
[formatter setGroupingSeparator:@""];
[formatter setDecimalSeparator:@"."];

// Decimal values read from any db are always written with no grouping separator and a comma for decimal.

NSNumber *numberFromString = [formatter numberFromString:@"12000.54"]];

[formatter setGroupingSeparator:@" "]; // Whatever you want here
[formatter setDecimalSeparator:@","]; // Whatever you want here

NSString *finalValue = [formatter stringFromNumber:numberFromString];

NSLog(@"%@",finalValue); // Print 12 000,54

Problem solved.

问题解决了。

回答by mxcl

The simplest solution I recently found is:

我最近发现的最简单的解决方案是：

NSString *localizedString = [NSString localizedStringWithFormat:@"%@", @1234567];

Also works with ints:

也适用于整数：

NSString *localizedString = [NSString localizedStringWithFormat:@"%d", 1234567];

Verified in Xcode 6 playground. But docs say this function has always existed.

在 Xcode 6 playground 中验证。但是文档说这个功能一直存在。

回答by Rinku

NSNumberFormatter *numberFormatter = [[NSNumberFormatter alloc] init];
[numberFormatter setNumberStyle:NSNumberFormatterDecimalStyle];
numberFormatter.usesGroupingSeparator = YES;
[numberFormatter setMaximumFractionDigits:2];
[numberFormatter setMinimumFractionDigits:2];
NSString *formattedNumberString = [numberFormatter stringFromNumber:@122344.00];`

This wll fix your rounding up problem if you are dealing with decimal points.

如果您正在处理小数点，这将解决您的舍入问题。

回答by Brandon Zacharie

For currency use...

对于货币使用...

let numberFormatter = NumberFormatter()

// Produces symbol (i.e. "$ " for en_US_POSIX) and decimal formatting
numberFormatter.numberStyle = .currency

// Produces commas; i.e. "1,234"
numberFormatter.usesGroupingSeparator = true
numberFormatter.groupingSize = 3

Example usage:

用法示例：

let value: Double = 12345.6789
numberFormatter.string(from: value as NSNumber)

yields...

产生...

"$?12,345.68"

as one would expect

正如人们所期望的那样