Python 同时执行多个.py文件
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Execute multiple .py files at the same time
提问by Petesta
I have three .py files that I want to run at the same time in a Python script file. I initially called subprocess.call()three times (once for each .py file) but remembered that it blocks until the command is finished. I tried subprocess.Popen(['screen', 'python_file'])since I believe it doesn't block but when I was checking for the processes with screen -lsthere was only one process running. How do I get all three programs running at the same time with a Python script? Should I be using the multiprocessingor multithreadinglibrary?
我想在 Python 脚本文件中同时运行三个 .py 文件。我最初调用了subprocess.call()3 次（每个 .py 文件调用一次），但记得它会阻塞直到命令完成。我尝试过，subprocess.Popen(['screen', 'python_file'])因为我相信它不会阻塞，但是当我检查进程时screen -ls，只有一个进程正在运行。如何使用 Python 脚本同时运行所有三个程序？我应该使用multiprocessing还是multithreading库？
Edit: The other processes aren't supposed to finish since they're running in an infinite loop. Here's exactly what I had in my Python script file. I'm using screenbecause each .py file has stdout logged onto the terminal and I want to be able to see what is being logged for each one.
编辑：其他进程不应该完成，因为它们在无限循环中运行。这正是我在 Python 脚本文件中的内容。我正在使用screen是因为每个 .py 文件都有标准输出登录到终端，我希望能够看到每个文件记录的内容。
subprocess.Popen(['screen', './submitter.py'])subprocess.Popen(['screen', './worker.py'])subprocess.Popen(['screen', './tester.py'])
subprocess.Popen(['screen', './submitter.py'])subprocess.Popen(['screen', './worker.py'])subprocess.Popen(['screen', './tester.py'])
采纳答案by xlharambe
If you want to use multiprocessing, you can try this:
如果你想使用multiprocessing，你可以试试这个：
import multiprocessing
def worker(file):
# your subprocess code
if __name__ == '__main__':
files = ["path/to/file1.py","path/to/file2.py","path/to/file3.py"]
for i in files:
p = multiprocessing.Process(target=worker, args=(i,))
p.start()
