带参数的 Laravel 路由
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/42359582/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Laravel route with parameters
提问by Prit
Am using laravel route for approving some form from email. So i have encrypted some variables and created link which is like
我正在使用 laravel 路线来批准电子邮件中的某些表格。所以我加密了一些变量并创建了链接，就像
<a href="http://localhost/travel/tr/approveRequest?id=<?=$Encoded_travelRq_id?>&gsID<?=$Encoded_emp_gslab_id?>&decrypt<?=$Encoded_iv?>/">Approve</a>;
now how route can be written for this on laravel side in which i can seperate the variables like id, gsID, decrypt from url and can send to controller's function used against that route?
现在如何在 Laravel 端为此编写路由，我可以在其中分离诸如 id、gsID、从 url 解密之类的变量，并可以发送到针对该路由使用的控制器函数？
回答by EddyTheDove
Simply write a GETroute to approveRequest:
简单地写一个GET路由到approveRequest：
Route::get('approveRequest', 'ApproveController@approve');
Because you are using URL parameters, you can simply get them in the approve()function like this
因为您使用的是 URL 参数，所以您可以approve()像这样简单地在函数中获取它们
public function approve(Request $request)
{
$id = $request->id;
$gsID = $request->get('gsID');
.... and so on for all your variables.
}
With this approach the order of parameters does not matter.
使用这种方法，参数的顺序无关紧要。
回答by Caio César Brito
Usually I use two ways:
通常我使用两种方式：
1o way:
1o方式：
The route:
路线：
Route::get('approveRequest', 'ApproveController@approve');
The controller:
控制器：
public function approve (Request $request) {
$var1 = $request->input('var1');
$var2 = $request->input('var2');
(...) do something with $var1 and $var2
}
2o way:
2o方式：
The route:
路线：
Route::get('approveRequest/{var1}/{var2}', 'ApproveController@approve');
The controller:
控制器：
public function approve ($var1, $var2) {
(...) do something with $var1 and $var2: they already have a instance
}
Good Luck! I hope be useful.
祝你好运！我希望有用。
回答by Sagar Arora
There are many methods to do this.
有很多方法可以做到这一点。
Method 1
方法一
If you make the url like below:
如果你像下面这样制作网址：
<a href="http://localhost/travel/tr/approveRequest/<?=$Encoded_travelRq_id?>/<?=$Encoded_emp_gslab_id?>/<?=$Encoded_iv?>">Approve</a>;
You can make route with parameters as like below.
您可以使用如下参数创建路由。
Route::get('approveRequest/{par1}/{par2}/{par3}', 'ApproveController@approve');
And in your function get the respective parameter as following:
并在您的函数中获取相应的参数如下：
public function approve($par1,$par2,$par3,)
{
$id = $par1;
$gsID = $par2;
.... and so on for all your variables.
}
Method 2 use request method:
方法二使用请求方法：
If your url is like:
如果你的网址是这样的：
<a href="http://localhost/travel/tr/approveRequest?id=<?=$Encoded_travelRq_id?>&gsID<?=$Encoded_emp_gslab_id?>&decrypt<?=$Encoded_iv?>/">Approve</a>;
Then define Route Like:
然后定义路由喜欢：
Route::post('approveRequest', 'ApproveController@approve');
Then in your controller function you get parameters as below:
然后在您的控制器功能中，您将获得如下参数：
Use Request after the namespace in youe controller class
在您的控制器类中的命名空间之后使用 Request
namespace App\Http\Controllers;
use Illuminate\Http\Request;
class SomeClassController extends Controller {
public function approve(Request $request)
{
$id = $request->id;
$gsID = $request->get('gsID');
.... and so on for all your variables.
}
}
