如何在 Java 中创建一个 zip 文件

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时间:2020-08-11 23:34:22  来源:igfitidea点击:

How to create a zip file in Java

javazip

提问by Ashish Agarwal

I have a dynamic text file that picks content from a database according to the user's query. I have to write this content into a text file and zip it in a folder in a servlet. How should I do this?

我有一个动态文本文件,它根据用户的查询从数据库中选取内容。我必须将此内容写入文本文件并将其压缩到 servlet 中的文件夹中。我该怎么做?

采纳答案by Chris

Look at this example:

看这个例子:

StringBuilder sb = new StringBuilder();
sb.append("Test String");

File f = new File("d:\test.zip");
ZipOutputStream out = new ZipOutputStream(new FileOutputStream(f));
ZipEntry e = new ZipEntry("mytext.txt");
out.putNextEntry(e);

byte[] data = sb.toString().getBytes();
out.write(data, 0, data.length);
out.closeEntry();

out.close();

This will create a zip in the root of D:named test.zipwhich will contain one single file called mytext.txt. Of course you can add more zip entries and also specify a subdirectory like this:

这将在D:named的根目录中创建一个 ziptest.zip文件,其中将包含一个名为.zip 的文件mytext.txt。当然,您可以添加更多 zip 条目并指定一个子目录,如下所示:

ZipEntry e = new ZipEntry("folderName/mytext.txt");

You can find more information about compression with Java here.

您可以在此处找到有关使用 Java 进行压缩的更多信息。

回答by WiseGeek

To write a ZIP file, you use a ZipOutputStream. For each entry that you want to place into the ZIP file, you create a ZipEntry object. You pass the file name to the ZipEntry constructor; it sets the other parameters such as file date and decompression method. You can override these settings if you like. Then, you call the putNextEntry method of the ZipOutputStream to begin writing a new file. Send the file data to the ZIP stream. When you are done, call closeEntry. Repeat for all the files you want to store. Here is a code skeleton:

要编写 ZIP 文件,请使用 ZipOutputStream。对于要放入 ZIP 文件的每个条目,您创建一个 ZipEntry 对象。您将文件名传递给 ZipEntry 构造函数;它设置其他参数,如文件日期和解压缩方法。如果您愿意,您可以覆盖这些设置。然后,调用 ZipOutputStream 的 putNextEntry 方法开始写入新文件。将文件数据发送到 ZIP 流。完成后,调用 closeEntry。对要存储的所有文件重复此操作。这是一个代码框架:

FileOutputStream fout = new FileOutputStream("test.zip");
ZipOutputStream zout = new ZipOutputStream(fout);
for all files
{
    ZipEntry ze = new ZipEntry(filename);
    zout.putNextEntry(ze);
    send data to zout;
    zout.closeEntry();
}
zout.close();

回答by Dhiral Pandya

public static void main(String args[])
{
    omtZip("res/", "omt.zip");
}
public static void omtZip(String path,String outputFile)
{
    final int BUFFER = 2048;
    boolean isEntry = false;
    ArrayList<String> directoryList = new ArrayList<String>();
    File f = new File(path);
    if(f.exists())
    {
    try {
            FileOutputStream fos = new FileOutputStream(outputFile);
            ZipOutputStream zos = new ZipOutputStream(new BufferedOutputStream(fos));
            byte data[] = new byte[BUFFER];

            if(f.isDirectory())
            {
               //This is Directory
                do{
                    String directoryName = "";
                    if(directoryList.size() > 0)
                    {
                        directoryName = directoryList.get(0);
                        System.out.println("Directory Name At 0 :"+directoryName);
                    }
                    String fullPath = path+directoryName;
                    File fileList = null;
                    if(directoryList.size() == 0)
                    {
                        //Main path (Root Directory)
                        fileList = f;
                    }else
                    {
                        //Child Directory
                        fileList = new File(fullPath);
                    }
                    String[] filesName = fileList.list();

                    int totalFiles = filesName.length;
                    for(int i = 0 ; i < totalFiles ; i++)
                    {
                        String name = filesName[i];
                        File filesOrDir = new File(fullPath+name);
                        if(filesOrDir.isDirectory())
                        {
                            System.out.println("New Directory Entry :"+directoryName+name+"/");
                            ZipEntry entry = new ZipEntry(directoryName+name+"/");
                            zos.putNextEntry(entry);
                            isEntry = true;
                            directoryList.add(directoryName+name+"/");
                        }else
                        {
                            System.out.println("New File Entry :"+directoryName+name);
                            ZipEntry entry = new ZipEntry(directoryName+name);
                            zos.putNextEntry(entry);
                            isEntry = true;
                            FileInputStream fileInputStream = new FileInputStream(filesOrDir);
                            BufferedInputStream bufferedInputStream = new BufferedInputStream(fileInputStream, BUFFER);
                            int size = -1;
                            while(  (size = bufferedInputStream.read(data, 0, BUFFER)) != -1  )
                            {
                                zos.write(data, 0, size);
                            }
                            bufferedInputStream.close();
                        }
                    }
                    if(directoryList.size() > 0 && directoryName.trim().length() > 0)
                    {
                        System.out.println("Directory removed :"+directoryName);
                        directoryList.remove(0);
                    }

                }while(directoryList.size() > 0);
            }else
            {
                //This is File
                //Zip this file
                System.out.println("Zip this file :"+f.getPath());
                FileInputStream fis = new FileInputStream(f);
                BufferedInputStream bis = new BufferedInputStream(fis,BUFFER);
                ZipEntry entry = new ZipEntry(f.getName());
                zos.putNextEntry(entry);
                isEntry = true;
                int size = -1 ;
                while(( size = bis.read(data,0,BUFFER)) != -1)
                {
                    zos.write(data, 0, size);
                }
            }               

            //CHECK IS THERE ANY ENTRY IN ZIP ? ----START
            if(isEntry)
            {
              zos.close();
            }else
            {
                zos = null;
                System.out.println("No Entry Found in Zip");
            }
            //CHECK IS THERE ANY ENTRY IN ZIP ? ----START
        }catch(Exception e)
        {
            e.printStackTrace();
        }
    }else
    {
        System.out.println("File or Directory not found");
    }
 }    

}

回答by Sivabalan

Java 7 has ZipFileSystem built in, that can be used to create, write and read file from zip file.

Java 7 内置了 ZipFileSystem,可用于从 zip 文件创建、写入和读取文件。

Java Doc: ZipFileSystem Provider

Java 文档:ZipFileSystem 提供程序

Map<String, String> env = new HashMap<>();
// Create the zip file if it doesn't exist
env.put("create", "true");

URI uri = URI.create("jar:file:/codeSamples/zipfs/zipfstest.zip");

try (FileSystem zipfs = FileSystems.newFileSystem(uri, env)) {
    Path externalTxtFile = Paths.get("/codeSamples/zipfs/SomeTextFile.txt");
    Path pathInZipfile = zipfs.getPath("/SomeTextFile.txt");          
    // Copy a file into the zip file
    Files.copy(externalTxtFile, pathInZipfile, StandardCopyOption.REPLACE_EXISTING); 
}

回答by cmujica

If you want decompress without software better use this code. Other code with pdf files sends error on manually decompress

如果您想在没有软件的情况下解压缩更好地使用此代码。其他带有 pdf 文件的代码在手动解压缩时发送错误

byte[] buffer = new byte[1024];     
    try
    {   
        FileOutputStream fos = new FileOutputStream("123.zip");
        ZipOutputStream zos = new ZipOutputStream(fos);
        ZipEntry ze= new ZipEntry("file.pdf");
        zos.putNextEntry(ze);
        FileInputStream in = new FileInputStream("file.pdf");
        int len;
        while ((len = in.read(buffer)) > 0) 
        {
            zos.write(buffer, 0, len);
        }
        in.close();
        zos.closeEntry();
        zos.close();
    }
    catch(IOException ex)
    {
       ex.printStackTrace();
    }

回答by Yuiffy

Spring boot controller, zip the files in a directory, and can be downloaded.

Spring boot 控制器,将文件压缩到一个目录中,并且可以下载。

@RequestMapping(value = "/files.zip")
@ResponseBody
byte[] filesZip() throws IOException {
    File dir = new File("./");
    File[] filesArray = dir.listFiles();
    if (filesArray == null || filesArray.length == 0)
        System.out.println(dir.getAbsolutePath() + " have no file!");
    ByteArrayOutputStream bo = new ByteArrayOutputStream();
    ZipOutputStream zipOut= new ZipOutputStream(bo);
    for(File xlsFile:filesArray){
        if(!xlsFile.isFile())continue;
        ZipEntry zipEntry = new ZipEntry(xlsFile.getName());
        zipOut.putNextEntry(zipEntry);
        zipOut.write(IOUtils.toByteArray(new FileInputStream(xlsFile)));
        zipOut.closeEntry();
    }
    zipOut.close();
    return bo.toByteArray();
}

回答by Siraj K

Since it took me a while to figure it out, I thought it would be helpful to post my solution using Java 7+ ZipFileSystem

由于我花了一段时间才弄明白,我认为使用 Java 7+ ZipFileSystem 发布我的解决方案会有所帮助

 openZip(runFile);

 addToZip(filepath); //loop construct;  

 zipfs.close();

 private void openZip(File runFile) throws IOException {
    Map<String, String> env = new HashMap<>();
    env.put("create", "true");
    env.put("encoding", "UTF-8");
    Files.deleteIfExists(runFile.toPath());
    zipfs = FileSystems.newFileSystem(URI.create("jar:" + runFile.toURI().toString()), env);    
 }

 private void addToZip(String filename) throws IOException {
    Path externalTxtFile = Paths.get(filename).toAbsolutePath();
    Path pathInZipfile = zipfs.getPath(filename.substring(filename.lastIndexOf("results"))); //all files to be stored have a common base folder, results/ in my case
    if (Files.isDirectory(externalTxtFile)) {
        Files.createDirectories(pathInZipfile);
        try (DirectoryStream<Path> ds = Files.newDirectoryStream(externalTxtFile)) {
            for (Path child : ds) {
                addToZip(child.normalize().toString()); //recursive call
            }
        }
    } else {
        // copy file to zip file
        Files.copy(externalTxtFile, pathInZipfile, StandardCopyOption.REPLACE_EXISTING);            
    }
 }

回答by Owen Cao

Here is an example code to compress a Whole Directory(including sub files and sub directories), it's using the walk file tree feature of Java NIO.

这是一个压缩整个目录(包括子文件和子目录)的示例代码,它使用了 Java NIO 的 walk 文件树功能。

import java.io.FileOutputStream;
import java.io.IOException;
import java.nio.file.*;
import java.nio.file.attribute.BasicFileAttributes;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;

public class ZipCompress {
    public static void compress(String dirPath) {
        final Path sourceDir = Paths.get(dirPath);
        String zipFileName = dirPath.concat(".zip");
        try {
            final ZipOutputStream outputStream = new ZipOutputStream(new FileOutputStream(zipFileName));
            Files.walkFileTree(sourceDir, new SimpleFileVisitor<Path>() {
                @Override
                public FileVisitResult visitFile(Path file, BasicFileAttributes attributes) {
                    try {
                        Path targetFile = sourceDir.relativize(file);
                        outputStream.putNextEntry(new ZipEntry(targetFile.toString()));
                        byte[] bytes = Files.readAllBytes(file);
                        outputStream.write(bytes, 0, bytes.length);
                        outputStream.closeEntry();
                    } catch (IOException e) {
                        e.printStackTrace();
                    }
                    return FileVisitResult.CONTINUE;
                }
            });
            outputStream.close();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
}

To use this, just call

要使用它,只需调用

ZipCompress.compress("target/directoryToCompress");

and you'll get a zip file directoryToCompress.zip

你会得到一个 zip 文件 directoryToCompress.zip

回答by live-love

This is how you create a zip file from a source file:

这是从源文件创建 zip 文件的方式:

String srcFilename = "C:/myfile.txt";
String zipFile = "C:/myfile.zip";

try {
    byte[] buffer = new byte[1024];
    FileOutputStream fos = new FileOutputStream(zipFile);
    ZipOutputStream zos = new ZipOutputStream(fos);         
    File srcFile = new File(srcFilename);
    FileInputStream fis = new FileInputStream(srcFile);
    zos.putNextEntry(new ZipEntry(srcFile.getName()));          
    int length;
    while ((length = fis.read(buffer)) > 0) {
        zos.write(buffer, 0, length);
    }
    zos.closeEntry();
    fis.close();
    zos.close();            
}
catch (IOException ioe) {
    System.out.println("Error creating zip file" + ioe);
}

回答by Pavel

Single file:

单个文件:

String filePath = "/absolute/path/file1.txt";
String zipPath = "/absolute/path/output.zip";

try (ZipOutputStream zipOut = new ZipOutputStream(new FileOutputStream(zipPath))) {
    File fileToZip = new File(filePath);
    zipOut.putNextEntry(new ZipEntry(fileToZip.getName()));
    Files.copy(fileToZip.toPath(), zipOut);
}

Multiple files:

多个文件:

List<String> filePaths = Arrays.asList("/absolute/path/file1.txt", "/absolute/path/file2.txt");
String zipPath = "/absolute/path/output.zip";

try (ZipOutputStream zipOut = new ZipOutputStream(new FileOutputStream(zipPath))) {
    for (String filePath : filePaths) {
        File fileToZip = new File(filePath);
        zipOut.putNextEntry(new ZipEntry(fileToZip.getName()));
        Files.copy(fileToZip.toPath(), zipOut);
    }
}